Analyze the free-body diagram, given the coefficients of static and kinetic friction.Determine whether the block will slide and the net force on the system.staticfriction is not shown, but must be inchuded in calculations!kineticHs = 0.25Hk = 0.2fs,max50fr =40T.W2 [N]slide?friction [N]friction|Fnetl [N]direction40yes, down-rigt v40up-left v22N-102NW28045up-left vWy = 200Nno(see table)W; = 225N30down-righ120no40down-righ18160yes, up-left5840down-righ200yes, up-leftcannot be determinedcheck answerschallengealine Calculatorsound 343m/sificant figuresJOV

Answered: Image /qna-images/answer/540c4105-048d-4c92-aa31-513ecd0c9324.jpg

Analyze the free-body diagram, given the coefficients of static and kinetic friction. Determine whether the block will slide and the net force on the system. static friction is not shown, but must be inchided in kinetic Hs = 0.25 Hk = 0.2 fs,max = 50 N. f = 40 friction W2 [N] slide? friction [N] |Fnetl [N] direction We102N 40 yes, down-rigt v 40 up-left 22 W2 (see table) Wy = 200N 45 up-left v 80 no W; 225N 30 down-righ no 120 18 40 down-righ 160 yes, up-left 58 down-righ 200 yes, up-left check answers

Analyze the free-body diagram, given the coefficients of static and kinetic friction. Determine whether the block will slide and the net force on the system. static friction is not shown, but must be inchided in kinetic Hs = 0.25 Hk = 0.2 fs,max = 50 N. f = 40 friction W2 [N] slide? friction [N] |Fnetl [N] direction We102N 40 yes, down-rigt v 40 up-left 22 W2 (see table) Wy = 200N 45 up-left v 80 no W; 225N 30 down-righ no 120 18 40 down-righ 160 yes, up-left 58 down-righ 200 yes, up-left check answers

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: Problem 4 - Two homogeneous rods ABCD and BE are bent as shown and rigidly connected to each other…

A: Two homogeneous Rods are given as shown in the image above and it has been asked in the question to…

Q: If a horizontal force of P = 100 N is applied perpendicular to the handle of the lever at A,…

A: FBD of the given problem:

Q: A 4.8-ft-long steel wire of 1/4 -in.-diameter is subjected to a 750-lb tensile load. Knowing that E…

A: This question is related to Strength of Material. In this question we calculate Elongated value of…

Q: If F=80 N, determine the magnitude and coordinate diretion angles of the couple moment. The pipe…

A: Given dataF=80 NFINDdetermine the magnitude and coordinate diretion angles of the couple moment

Q: 5 ft 7.84 Find the smallest angle B for which the uniform crate can be tipped about corner A. Also…

A: Show the free body diagram of the uniform crate as in Figure (1).

Q: De Ex 2m

Q: 2. A 30 m steel tape standardized at 20°C and supported throughout under a tension of 5.45 kg was…

A: length of tape L=30m Standard temperature = 200C Cross section area = 0.05 cm2 To find: The correct…

Q: Determine the force of member BD. Include a negative sign if the answer is in compression. Indicate…

Q: A reinforced concrete beam has a width of 250mm and a total depth of 450mm. It is reinforced with a…

A: Given Data:b=250mmD=450mmAst=1875mm2Effective depth d = 375mmfc=21MpaFy = 233MpaTo Find: Moment…

Q: Determine the force in each member of the truss shown by the method of joints. Show free body…

Q: A rigid bar AD is hanged by two steel cables of diameter 0.065 in as shown in the figure. Find: a)…

Q: Shown in Fig. P-255 is a section through a balcony. The total uniform load of 600 kN-is supported by…

Q: The uniform concrete pipe has a weight of 800 lb and is unloaded slowly from the truck bed using the…

A: consider the following free body diagram use the equilibrium conditions as follows :ΣMA = 0-800 x r…

Q: Q3- Determine minimum yield stress requiredfor fabricating the pipe shown in figure (Q3). The pipe…

A: Tresca's theory by this theory material will fail when the value of the maximum shear stress…

Q: (continuation) 300 mm A Q 450 mm C Y Fig. RN-21 Determine the area of the region (in square…

Q: The column is used to support the upper floor. If a force F = 80 N is applied perpendicular to the…

A: Given data:

Q: For the beam and loading shown, calculate (a) the equation of the elastic curve, (b) the deflection…

Q: S79 The light bar is used to support the 50-kg block in its vertical guides. If the coefficient of…

Q: ol boeu et thede s sib -0E biloe on 5-5. The copper pipe has an outer diameter of 2.50 in. and an…

Q: 600 N B. 60° 30 50 mm

Q: Required information NOTE: This is a multi-part question. Once an answer is submitted, you will be…

Concept explainers

Laws of Equilibrium

A body is said to be in equilibrium if the system of forces acting on the body tends to keep the body at rest, in other words, there is no translation motion or net torque on the body. Under such conditions, the equilibrium conditions are to be applied to analyze the condition. The branch of mechanics that deals with this condition is known as 'statics'. Under equilibrium, there are no net forces on the body.

Question

Analyze the free-body diagram, given the coefficients of static and kinetic friction.
Determine whether the block will slide and the net force on the system.
static
friction is not shown, but must be inchuded in calculations!
kinetic
Hs = 0.25
Hk = 0.2
fs,max
50
fr =
40
T.
W2 [N]
slide?
friction [N]
friction
|Fnetl [N]
direction
40
yes, down-rigt v
40
up-left v
22
N-102N
W2
80
45
up-left v
Wy = 200N
no
(see table)
W; = 225N
30
down-righ
120
no
40
down-righ
18
160
yes, up-left
58
40
down-righ
200
yes, up-left
cannot be determined
check answers
challenge
aline Calculator
sound 343m/s
ificant figures
JOV

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

C A 10 FBD E TI X compute horizontal and vertical displacement at Cusing a) differential equation b) conjugate beam c) unit load t EMA = = - MA + Fa {Fy (include moment) diagram =0
Whats the free body diagram on this problem.
1-21_Problems Q:1/ A hollow right-circular cylinder is made of cast iron and has an outside diameter of (75 mm) and an inside diameter of (60 mm). If the cylinder is loaded by an axial compressive force of (50 kN), determine the total shortening in a (600 mm) length. Also determine the normal stress under this load. Take the modulus of elasticity to be (100 GPa). Ans.(ô = 0.188 mm) , (o= 31.45 MPa) Q:2/A square steel bar is (50 mm) on a side and (250 mm) long. It is loaded by an axial tensile force of (200 kN). If(E= 200 GPa) and (µ= 0.3), determine the change of volume per unit volume. (Ans. 0.00016) Q:3/The bar shown in Fig.(1-22 ) is subjected to a tensile load of (160kN). If the stress in the middle portion is limited to (150N/mm³), determine the diameter of middle portion. Find also the length of the middle portion if the total elongation of the bar is to be (0.2mm). Young's modulus is given as equal to (2.1*10$ N/mm³). (Ans. d= 3.68em , L=20.71em) 160 KN A 6 cm DIA 160 N 6 om DIA…
If the clamping force at G is 900 N, determine the horizontal force F that must be applied perpendicular to the handle of the lever at E. The mean diameter and lead of both single square-threaded screws at C and D are 25 mm and 5 mm, respectively. The coefficient of static friction is μ = 0.3. Answer: F = 66.7N 200 mm- -200 mm OA C 125 mm
To = 4.31 kN.m
Show the complete solution for this equation
Determine the reactions of A & B for the steel bon and leasing as given abuming that 4.5 mm clearance exist bin the bar and the ground before the loads are applied. Assume E = 200 GPG. P₁ = 300 KN P₂ = 600 KN A₁ = 250 mm² A₂ = 400 mm² 5 R 4 3 2 1 & P VA 0 B P₂ 150mm 150m 150mm 150mm 4.Sm
The uniform concrete pipe has a weight of 800 lband is unloaded slowly from the truck bed using the ropeand skids shown. If the coefficient of kinetic frictionbetween the rope and pipe is μk = 0.3, determine the forcethe worker must exert on the rope to lower the pipe atconstant speed. There is a pulley at B, and the pipe does notslip on the skids. The lower portion of the rope is parallel tothe skids.