Analyze The directions of the individual forces exerted by q, and q, on qz are shown in the figure. The force F23 exerted by q, on q3 is (---Select--because q, and q, have opposite signs. In the coordinate systemshown in the figure, the force F23 is to the left (in the negative x-direction).The force F,3 exerted by q, on 93 is--Select--- +) because both charges are positive. The force F.13makes an angle of 45.0° with the x-axis.Use Coulomb's law to find the magnitude of F23 (in N):192|193|F23 = kea2NFind the magnitude of the force F13 (in N):19.|193|F13 = Ke(vz a)?NFind the x- and y-components of the force F13 (in N):F13xF13y(F13)cos(45.0°) =(F13)sin(45.0°) =NNFind the components of the resultant force (in N) acting on q3:F3x = F13x + F23xN + (-4.37 N)F3y = F13y + F23yN + ONExpress the resultant force (in N) acting on q3 in unit-vector form:F, (5) Nî +3. Consider three point charges located at the corners of a right triangle as shown in the figure, where q, = 933 3.50 иС, q2= -2.00 µC, and a = 0.120 m. Find the resultant force exerted on g3.The force exerted by q, on q, is F13: The forceexerted by q2 on 93 is F23. The resultant force F3is the vector sum F13 + F23·a239293a2a91 +

Answered: Image /qna-images/answer/54b484bb-816e-4481-ae52-0d370556d163.jpg

Analyze The directions of the individual forces exerted by q, and q, on 9z are shown in the figure. The force F23 exerted by 9, on 9z is -Select--- because q, and 9, have opposite signs. In the coordinate sys shown in the figure, the force F23 is to the left (in the negative x-direction). The force F,, exerted by q, on q, is -Select- 9 because both charges are positive. The force F,a makes an angle of 45.0° with the x-axis. 93 Use Coulomb's law to find the magnitude of F22 (in N): 192|193| F23 = ke a2 Find the magnitude of the force F13 (in N): F13 = ketvz a)2 Find the x- and y-components of the force F,3 (in N): F13x - (F13)cos(45.0°) = F13y = (F13)sin(45.0°) = Find the components of the resultant force (in N) acting on 93: F3x = F13x + F23x = F3y = F13y + F23y = N + (-4.37 N) N +ON Express the resultant force (in N) acting on 9z in unit-vector form: i+

Analyze The directions of the individual forces exerted by q, and q, on 9z are shown in the figure. The force F23 exerted by 9, on 9z is -Select--- because q, and 9, have opposite signs. In the coordinate sys shown in the figure, the force F23 is to the left (in the negative x-direction). The force F,, exerted by q, on q, is -Select- 9 because both charges are positive. The force F,a makes an angle of 45.0° with the x-axis. 93 Use Coulomb's law to find the magnitude of F22 (in N): 192|193| F23 = ke a2 Find the magnitude of the force F13 (in N): F13 = ketvz a)2 Find the x- and y-components of the force F,3 (in N): F13x - (F13)cos(45.0°) = F13y = (F13)sin(45.0°) = Find the components of the resultant force (in N) acting on 93: F3x = F13x + F23x = F3y = F13y + F23y = N + (-4.37 N) N +ON Express the resultant force (in N) acting on 9z in unit-vector form: i+

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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