Analysis of Data: Since half life is defined as: t₁/2 = T ln2 = (RC) ln2 lngad to noticias Sho = t1/2 R ln2 then Cexperimental nesly Calculate the percent difference between the actual value of the capacitance (from the digital multimeter measurement) and the experimental value: booo11 =
Analysis of Data: Since half life is defined as: t₁/2 = T ln2 = (RC) ln2 lngad to noticias Sho = t1/2 R ln2 then Cexperimental nesly Calculate the percent difference between the actual value of the capacitance (from the digital multimeter measurement) and the experimental value: booo11 =
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Half life voltage V1/2= 4.5 V
time to half-max t1/2=6.7 seconds
Transcribed Image Text:Analysis of Data:
Since half life is defined as: t₁/2 = T ln2 = (RC) In2
then experimental
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Conclusion:
Subs
3
t1/2
R ln2
TONGA
=
Calculate the percent difference between the actual value of the capacitance (from the
digital multimeter measurement) and the experimental value:
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She
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![Actual capacitance is:
10.27
Actual resistance is:
[uf] and lei
Switch the multimeter to the resistance mode and measure the actual resistance of the
given resistor (or the system of smaller resistances).
1.00
letomatiq
IMX
of wh](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F50351a65-5e52-4545-9e5a-caf58e03b0d0%2F77715c72-ebfb-45a8-9a44-8af3a334d317%2F5ntr00c_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Actual capacitance is:
10.27
Actual resistance is:
[uf] and lei
Switch the multimeter to the resistance mode and measure the actual resistance of the
given resistor (or the system of smaller resistances).
1.00
letomatiq
IMX
of wh
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