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ANALYSIS Calculations: A1. (Refer back to Figure 3 for help with these calculations) The following data and calculations refer to the water in the calorimeter. Calculate the requested quantities from your data and enter the results in the table. Show all equations and work with units. Final: reMp. TEMP. change in temperature of water in calorimeter = - Initial (23.23°C-20°C) = 3.23°C Water 75 9M mwater = ニ cal 1.00 g "C SHwater = heat energy absorbed by water in calorimeter = る。23℃ 242.25 calI Heat =M•SH AT ATwater = =15.09X qwater = F75.0gx 1.00 cal x 3.23 cal = 242.25 cal.- A2. The following data and calculations refer to the metal. Calculate the requested quantities from your data and enter the results in the table. Show all equations and work with units. Metal change in temperature of the metal cylinder = mmetal = SHmetal = ? ATmetal = how much heat energy did the metal transfer to the water? (remember the Law of Conservation of Energy) qmetal = calculate the specific heat of the metal in (show equation and work). cal g°C

ANALYSIS Calculations: A1. (Refer back to Figure 3 for help with these calculations) The following data and calculations refer to the water in the calorimeter. Calculate the requested quantities from your data and enter the results in the table. Show all equations and work with units. Final: reMp. TEMP. change in temperature of water in calorimeter = - Initial (23.23°C-20°C) = 3.23°C Water 75 9M mwater = ニ cal 1.00 g "C SHwater = heat energy absorbed by water in calorimeter = る。23℃ 242.25 calI Heat =M•SH AT ATwater = =15.09X qwater = F75.0gx 1.00 cal x 3.23 cal = 242.25 cal.- A2. The following data and calculations refer to the metal. Calculate the requested quantities from your data and enter the results in the table. Show all equations and work with units. Metal change in temperature of the metal cylinder = mmetal = SHmetal = ? ATmetal = how much heat energy did the metal transfer to the water? (remember the Law of Conservation of Energy) qmetal = calculate the specific heat of the metal in (show equation and work). cal g°C

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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ANALYSIS Calculations: A1. (Refer back to Figure 3 for help with these calculations) The following data and calculations refer to the water in the calorimeter. Calculate the requested quantities from your data and enter the results in the table. Show all equations and work with units. Final: Temp, change in temperature of water in calorimeter = - Initial (23.23°C-20°C) = 3.23°C Water TEMP. 75 9M mwater = ニ cal heat energy absorbed by water in calorimeter = SHwater = 1.00 g °C る。23℃ 242.25 caI Heat =M•SH AT ATwater = =15.09X qwater = F75.09x 1.0O cal x 3.23 cal = 242.25 cal.- A2. The following data and calculations refer to the metal. Calculate the requested quantities from your data and enter the results in the table. Show all equations and work with units. Metal change in temperature of the metal cylinder = mmetal = SHmetal = ATmetal = how much heat energy did the metal transfer to the water? (remember the Law of Conservation of Energy) qmetal = calculate the specific heat of the metal in (show equation and work). cal g°C Calculate the specific heat of the metal in . (1 cal = 4.184 J) (show work). Click on the box in the simulation that shows the value of the specific heat in these units and compare. Are your calculations correct?
Transcribed Image Text:ANALYSIS Calculations: A1. (Refer back to Figure 3 for help with these calculations) The following data and calculations refer to the water in the calorimeter. Calculate the requested quantities from your data and enter the results in the table. Show all equations and work with units. Final: Temp, change in temperature of water in calorimeter = - Initial (23.23°C-20°C) = 3.23°C Water TEMP. 75 9M mwater = ニ cal heat energy absorbed by water in calorimeter = SHwater = 1.00 g °C る。23℃ 242.25 caI Heat =M•SH AT ATwater = =15.09X qwater = F75.09x 1.0O cal x 3.23 cal = 242.25 cal.- A2. The following data and calculations refer to the metal. Calculate the requested quantities from your data and enter the results in the table. Show all equations and work with units. Metal change in temperature of the metal cylinder = mmetal = SHmetal = ATmetal = how much heat energy did the metal transfer to the water? (remember the Law of Conservation of Energy) qmetal = calculate the specific heat of the metal in (show equation and work). cal g°C Calculate the specific heat of the metal in . (1 cal = 4.184 J) (show work). Click on the box in the simulation that shows the value of the specific heat in these units and compare. Are your calculations correct?
identity of metal =tin %3D mass of metal, mmetal = 40.0g initial temperature of metal, Timetal = 140.0°C %3D mass of water, mwater = 5.09 %3D initial temperature of water, Tiwater = 20.0°C %3D final temp. of water and metal, Tr = 23,23 c %3D
Transcribed Image Text:identity of metal =tin %3D mass of metal, mmetal = 40.0g initial temperature of metal, Timetal = 140.0°C %3D mass of water, mwater = 5.09 %3D initial temperature of water, Tiwater = 20.0°C %3D final temp. of water and metal, Tr = 23,23 c %3D
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