Analysis 13--0² while(> 1) ( 13-18 while (j

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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HwQ2
### 2.) Analysis

```plaintext
i ← m;
while(i > b) {
    j ← i;  //*** CAUTION: this DOES NOT START AT 0
    while(j < n) {
        k ← 0;
        while(k < n) {
            k = k + 2;
        }
        j ← j * 2;
    }
    i ← i / 2;
}
```

#### Explanation:

The code uses nested loops to perform a series of operations. Here’s a breakdown:

1. **Outer Loop**: The variable `i` is initialized to `m` and continually halved until it is no longer greater than `b`.

2. **Middle Loop**: The variable `j`, starting from `i`, doubles in each iteration until it is not less than `n`.

3. **Innermost Loop**: The variable `k` increments by 2 in each iteration until it is not less than `n`.

#### Prompt Question:

What is the asymptotic upper bound of the code above?

Analyze the loops to determine the time complexity and find the tightest asymptotic upper bound for the given pseudocode.
Transcribed Image Text:### 2.) Analysis ```plaintext i ← m; while(i > b) { j ← i; //*** CAUTION: this DOES NOT START AT 0 while(j < n) { k ← 0; while(k < n) { k = k + 2; } j ← j * 2; } i ← i / 2; } ``` #### Explanation: The code uses nested loops to perform a series of operations. Here’s a breakdown: 1. **Outer Loop**: The variable `i` is initialized to `m` and continually halved until it is no longer greater than `b`. 2. **Middle Loop**: The variable `j`, starting from `i`, doubles in each iteration until it is not less than `n`. 3. **Innermost Loop**: The variable `k` increments by 2 in each iteration until it is not less than `n`. #### Prompt Question: What is the asymptotic upper bound of the code above? Analyze the loops to determine the time complexity and find the tightest asymptotic upper bound for the given pseudocode.
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The code consists of three nested loops. Let's break down the time complexity of each part:

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