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An urn contains m number of red balls and n number of white balls. Two balls are selected without replacement at random from the urn. Prove P(first ball is red | second ball is white) = m/(m+n-1)

An urn contains m number of red balls and n number of white balls. Two balls are selected without replacement at random from the urn. Prove P(first ball is red | second ball is white) = m/(m+n-1)

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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An urn contains m number of red balls and n number of white balls. Two balls are selected without replacement at random from the urn. Prove P(first ball is red | second ball is white) = m/(m+n-1)

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