An urn contains 8 red balls and 3 green balls. If Tim chooses 6 balls at random from the urn, what is the probability that he will select 4 red balls and 2 green balls? Round your answer to 3 decimal places. (If necessary, consult a list of formulas.)

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O PROBABILITY
Shasia v
Probabilities of draws without.
QUESTION
A history class is comprised of 4 female and 10 male students. If
instructor of the class randomly chooses 12 students from the cla
an oral exam, what is the probability that 3 female students and
students will be selected? Round your answer to 3 decimal place
(If necessary, consult a list of formulas.)
O EXPLANATION
We first count the number of different sets of 12 students that ca
selected from a class of 4+ 10=14 students. This is the number of
combinations of 14 items taken 12 at a time, which is equal to the
following.
14!
14C12-
= 91
12!2!
Other notations
The 91 different sets of 12 students can be considered as a sampl
Notice that each of the 91 sets of students in the sample space is
likely to be selected.
We next count the number of sets of students in the sample spa
have 3 female students and 9 male students. There are c, ways
the set of 3 female students from a class containing 4 female stu
and there are „C, ways to select the set of 9 male students from
containing 10 male students. Using the multiplication principle, we find the
of ways to select 3 female and 9 male students.
4!
„Cy'10C9= 311! 9!1!
10!
= 4-10-40
Therefore, we get the following.
P(instructor selects 3 female and 9 male students)
40
=0.44
91
ANSWER
0.44
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Transcribed Image Text:8:03 AA www-awn.aleks.com O PROBABILITY Shasia v Probabilities of draws without. QUESTION A history class is comprised of 4 female and 10 male students. If instructor of the class randomly chooses 12 students from the cla an oral exam, what is the probability that 3 female students and students will be selected? Round your answer to 3 decimal place (If necessary, consult a list of formulas.) O EXPLANATION We first count the number of different sets of 12 students that ca selected from a class of 4+ 10=14 students. This is the number of combinations of 14 items taken 12 at a time, which is equal to the following. 14! 14C12- = 91 12!2! Other notations The 91 different sets of 12 students can be considered as a sampl Notice that each of the 91 sets of students in the sample space is likely to be selected. We next count the number of sets of students in the sample spa have 3 female students and 9 male students. There are c, ways the set of 3 female students from a class containing 4 female stu and there are „C, ways to select the set of 9 male students from containing 10 male students. Using the multiplication principle, we find the of ways to select 3 female and 9 male students. 4! „Cy'10C9= 311! 9!1! 10! = 4-10-40 Therefore, we get the following. P(instructor selects 3 female and 9 male students) 40 =0.44 91 ANSWER 0.44 More Practice r Privacy | Accessibility
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O PROBABILITY
Probabilities of draws without...
An urn contains 8 red balls and 3 green balls. If Tim chooses 6 balls at
random from the urn, what is the probability that he will select 4 red
balls and 2 green balls? Round your answer to 3 decimal places.
(If necessary, consult a list of formulas.)
Explanation
Check
Terms of Use I Privacy Accessibility
II
Transcribed Image Text:AA A www-awn.aleks.com Bb Week 7 – MA... Bb Week 7 – MA... A Timed Out Home | iCam.. Bb Week 7 – MA... X Gibbs - Learn O PROBABILITY Probabilities of draws without... An urn contains 8 red balls and 3 green balls. If Tim chooses 6 balls at random from the urn, what is the probability that he will select 4 red balls and 2 green balls? Round your answer to 3 decimal places. (If necessary, consult a list of formulas.) Explanation Check Terms of Use I Privacy Accessibility II
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