An urn contains 3 orange balls and 5 yellow balls. If Sam chooses 5 balls at random from the urn, what is the probability that he will select 2 orange balls and 3 yellow balls? Round your answer to 3 decimal places. (If necessary, consult a list of formulas.)

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### Probability of Selecting Balls with Specific Colors

**Problem Statement:**
An urn contains 3 orange balls and 5 yellow balls. If Sam chooses 5 balls at random from the urn, what is the probability that he will select 2 orange balls and 3 yellow balls? Round your answer to 3 decimal places.

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**Instructions for Solving the Problem:**

1. **Determine the total number of ways to choose 5 balls out of 8:**
   Use the combination formula: C(n, k) = n! / (k!(n-k)!)
   Here, n = 8 (total balls) and k = 5 (balls chosen).
   
2. **Calculate the combinations for selecting 2 orange balls out of 3:**
   Use the combination formula: C(n, k) = n! / (k!(n-k)!)
   Here, n = 3 (orange balls) and k = 2 (balls chosen).
   
3. **Calculate the combinations for selecting 3 yellow balls out of 5:**
   Use the same combination formula.
   Here, n = 5 (yellow balls) and k = 3 (balls chosen).
   
4. **Compute the probability:**
   - Multiply the combinations of selecting orange balls with the combinations of selecting yellow balls.
   - Divide the result by the total number of ways to choose 5 balls out of 8.

5. **Round the probability to 3 decimal places.**

(If necessary, consult a [list of formulas](#) or use online combinations calculators to simplify the calculations.)

### Interactive Widget

[ ☐ | Calculate | Reset | Help? ]

---
This exercise helps students understand the application of combinations in probability. By dividing the problem into structured steps, calculations become more manageable, and students can better grasp the concept of combinatorial probability.
Transcribed Image Text:### Probability of Selecting Balls with Specific Colors **Problem Statement:** An urn contains 3 orange balls and 5 yellow balls. If Sam chooses 5 balls at random from the urn, what is the probability that he will select 2 orange balls and 3 yellow balls? Round your answer to 3 decimal places. --- **Instructions for Solving the Problem:** 1. **Determine the total number of ways to choose 5 balls out of 8:** Use the combination formula: C(n, k) = n! / (k!(n-k)!) Here, n = 8 (total balls) and k = 5 (balls chosen). 2. **Calculate the combinations for selecting 2 orange balls out of 3:** Use the combination formula: C(n, k) = n! / (k!(n-k)!) Here, n = 3 (orange balls) and k = 2 (balls chosen). 3. **Calculate the combinations for selecting 3 yellow balls out of 5:** Use the same combination formula. Here, n = 5 (yellow balls) and k = 3 (balls chosen). 4. **Compute the probability:** - Multiply the combinations of selecting orange balls with the combinations of selecting yellow balls. - Divide the result by the total number of ways to choose 5 balls out of 8. 5. **Round the probability to 3 decimal places.** (If necessary, consult a [list of formulas](#) or use online combinations calculators to simplify the calculations.) ### Interactive Widget [ ☐ | Calculate | Reset | Help? ] --- This exercise helps students understand the application of combinations in probability. By dividing the problem into structured steps, calculations become more manageable, and students can better grasp the concept of combinatorial probability.
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