An upright isosceles triangular plane surface, with base of 5 ft and a height of 6 ft, is submerged in a liquid of S.G.=0.69. The vertex of the triangular plane surface is located 4 ft below the liquid surface, while the plane of the triangle is inclined at an angle of 35° with respect to the horizontal. Solve for the total hydrostatic force acting on the plane surface and its corresponding location of line of action

An upright isosceles triangular plane surface, with base of 5 ft and a height of 6 ft, is submerged in a liquid of S.G.=0.69. The vertex of the triangular plane surface is located 4 ft below the liquid surface, while the plane of the triangle is inclined at an angle of 35° with respect to the horizontal. Solve for the total hydrostatic force acting on the plane surface and its corresponding location of line of action

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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