An upright arrow, 1.5 cm tall, is placed a distance 2.0 cm in front of a convex lens(lens 1) As a result, an upright image(image 1) of height 4.5 cm is formed on the same side of the lens 1 as the arrow. a) What is the length of (f sub 1) of lens 1? Is image 1 real or virtual? b) A second lens (lens 2) is now placed behind the first one, and an inverted image(image 2) of the arrow is observed a distance 4.0 cm behind lens . The height of image 2 is 1.5cm. Is image 2 real or virtual? What is the focal length of lens ? is it concave or covex? how far is lens 2 from lens 1? c) draw a ray diagram with a scale of 1:1 for the two-lense system based on the results of your calculation above.

icon
Related questions
Question

An upright arrow, 1.5 cm tall, is placed a distance 2.0 cm in front of a convex lens(lens 1) As a result, an upright image(image 1) of height 4.5 cm is formed on the same side of the lens 1 as the arrow.

a) What is the length of (f sub 1) of lens 1? Is image 1 real or virtual?

b) A second lens (lens 2) is now placed behind the first one, and an inverted image(image 2) of the arrow is observed a distance 4.0 cm behind lens . The height of image 2 is 1.5cm. Is image 2 real or virtual? What is the focal length of lens ? is it concave or covex? how far is lens 2 from lens 1?

c) draw a ray diagram with a scale of 1:1 for the two-lense system based on the results of your calculation above.

 

The image for the problem is attached.

lens /
len 2
3)
ob jeut
l.0cm
E 2,0 cuM
->
Transcribed Image Text:lens / len 2 3) ob jeut l.0cm E 2,0 cuM ->
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps with 4 images

Blurred answer
Similar questions