**Problem Statement:**An unknown metal with a mass of 160.4 g is dropped into a cylinder containing 150 g of water, and the water level rises to 172 mL. What is the identity of the metal given the densities listed?- Copper (8.96 g/mL)- Aluminum (2.7 g/mL)- Zinc (7.13 g/mL)**Explanation of Concept:**To find the identity of the metal, we can calculate its volume by using the water displacement method, which tells us that the volume of the metal is equal to the change in water level. Then, we use this volume to calculate the density of the metal and compare it with the given options to identify the metal.**Calculations:**1. Initial water level: 150 mL2. Final water level: 172 mL3. Volume of the metal = Final water level - Initial water level = 172 mL - 150 mL = 22 mL4. Density of the metal = Mass / Volume = 160.4 g / 22 mL ≈ 7.29 g/mL**Conclusion:**Comparing the calculated density of 7.29 g/mL with the given densities:- Copper: 8.96 g/mL- Aluminum: 2.7 g/mL- Zinc: 7.13 g/mLThe closest match is Zinc, with a density of 7.13 g/mL. Thus, the identity of the metal is likely Zinc.

Answered: Image /qna-images/answer/aa18c0fb-4332-48a0-87d0-d8efe2698fa4.jpg

An unknown metal with a mass of 160.4 g is dropped into a cylinder containing 150 g of water, and the water level rises to 172 mL. What is the identify of the metal given the densities listed? Copper (8.96 g/mL) Aluminum (2.7 g/mL) O Zinc (7.13 g/mL)

An unknown metal with a mass of 160.4 g is dropped into a cylinder containing 150 g of water, and the water level rises to 172 mL. What is the identify of the metal given the densities listed? Copper (8.96 g/mL) Aluminum (2.7 g/mL) O Zinc (7.13 g/mL)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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**Problem Statement:**

An unknown metal with a mass of 160.4 g is dropped into a cylinder containing 150 g of water, and the water level rises to 172 mL. What is the identity of the metal given the densities listed?

- Copper (8.96 g/mL)
- Aluminum (2.7 g/mL)
- Zinc (7.13 g/mL)

**Explanation of Concept:**

To find the identity of the metal, we can calculate its volume by using the water displacement method, which tells us that the volume of the metal is equal to the change in water level. Then, we use this volume to calculate the density of the metal and compare it with the given options to identify the metal.

**Calculations:**

1. Initial water level: 150 mL
2. Final water level: 172 mL
3. Volume of the metal = Final water level - Initial water level = 172 mL - 150 mL = 22 mL

4. Density of the metal = Mass / Volume = 160.4 g / 22 mL ≈ 7.29 g/mL

**Conclusion:**

Comparing the calculated density of 7.29 g/mL with the given densities:
- Copper: 8.96 g/mL
- Aluminum: 2.7 g/mL
- Zinc: 7.13 g/mL

The closest match is Zinc, with a density of 7.13 g/mL. Thus, the identity of the metal is likely Zinc.

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