An unknown amount of sodium hydroxide (FW= 40) was dissolved in 500 mL distilled water before standardized using 0.4928 g of potassium acid phthalate (MW = 204.23) in 75 mL distilled water. Calculate the unknown amount of sodium hydroxide in gram if the standardization needs 25.3 mL of sodium hydroxide to achieve the titration end point and the stoichiometric reaction between sodium hydroxide and potassium acid phthalate is one mole to one mole. (Note: FW = formula weight, MW = molecular weight)

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An unknown amount of sodium hydroxide (FW= 40) was dissolved in 500 mL distilled water before
standardized using 0.4928 g of potassium acid phthalate (MW = 204.23) in 75 mL distilled water.
Calculate the unknown amount of sodium hydroxide in gram if the standardization needs 25.3 mL
of sodium hydroxide to achieve the titration end point and the stoichiometric reaction between
sodium hydroxide and potassium acid phthalate is one mole to one mole. (Note: FW = formula
weight, MW = molecular weight)
Transcribed Image Text:An unknown amount of sodium hydroxide (FW= 40) was dissolved in 500 mL distilled water before standardized using 0.4928 g of potassium acid phthalate (MW = 204.23) in 75 mL distilled water. Calculate the unknown amount of sodium hydroxide in gram if the standardization needs 25.3 mL of sodium hydroxide to achieve the titration end point and the stoichiometric reaction between sodium hydroxide and potassium acid phthalate is one mole to one mole. (Note: FW = formula weight, MW = molecular weight)
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