In an RLC series circuit, the voltage amplitude and frequency of the source are 100 V and 500 Hz, respectively, and R = 520 0, L = 0.22 H, and C = 2.8 pF.(a) What is the impedance of the circuit (in 0)?776.8(b) What is the amplitude of the current from the source (in A)?0.120A(c) If the emf of the source is given by v(t) = (100 V)sin(1,000nt), how does the current vary with time? (Use the following as necessary: t. Assume i(t) is in amps and t is in seconds. Do not include units in your answer.)i(t) =(0.129)sin(1000t – 0.64)(d) Repeat the calculations with C changed to 0.28 pF.z = 685.5A0 = 0.148i(t) = (0.140) sin(1000nt – 0.58)

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