**Problem:**An RLC series circuit has an applied voltage of 277 volts. The inductor has a voltage drop of 355 volts and the capacitor has a voltage drop of 124 volts. What is the voltage drop across the resistor?**Solution:**To find the voltage drop across the resistor in an RLC series circuit, we use the formula for the total applied voltage in a series circuit:\[ V_{total} = V_R + V_L - V_C \]Where:- \( V_{total} \) is the total applied voltage.- \( V_R \) is the voltage drop across the resistor.- \( V_L \) is the voltage drop across the inductor.- \( V_C \) is the voltage drop across the capacitor.Given:- \( V_{total} = 277 \) volts- \( V_L = 355 \) volts- \( V_C = 124 \) voltsSolving for \( V_R \):\[ V_R = V_{total} - V_L + V_C \]\[ V_R = 277 - 355 + 124 \]\[ V_R = 46 \] voltsTherefore, the voltage drop across the resistor is 46 volts.

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Engineering

Electrical Engineering

An RLC series circuit has an annlied voltage of 277-

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Question

**Problem:**

An RLC series circuit has an applied voltage of 277 volts. The inductor has a voltage drop of 355 volts and the capacitor has a voltage drop of 124 volts. What is the voltage drop across the resistor?

**Solution:**

To find the voltage drop across the resistor in an RLC series circuit, we use the formula for the total applied voltage in a series circuit:

\[ V_{total} = V_R + V_L - V_C \]

Where:
- \( V_{total} \) is the total applied voltage.
- \( V_R \) is the voltage drop across the resistor.
- \( V_L \) is the voltage drop across the inductor.
- \( V_C \) is the voltage drop across the capacitor.

Given:
- \( V_{total} = 277 \) volts
- \( V_L = 355 \) volts
- \( V_C = 124 \) volts

Solving for \( V_R \):

\[ V_R = V_{total} - V_L + V_C \]

\[ V_R = 277 - 355 + 124 \]

\[ V_R = 46 \] volts

Therefore, the voltage drop across the resistor is 46 volts.

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