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An R-C series circuit has a supply voltage of 100 V. The resistance is 200 ohms and the capacitance is 0.0001 Farad. Match each item to a choice: Solve for the current "i' at any time 't". Solve for the charge "q" at any time "t'. Choices: # none of these i(t) = 0.25e-50t i(t) = -0.50e-50t i(t) = -0.= -1 1 (10 – e-50t) (10+ e¬60t) 103 i(t) = 0.50 q(t) 9(t) = 100 ; ! none of these 1 q(t) = (1 – e-30*) 10 :::

An R-C series circuit has a supply voltage of 100 V. The resistance is 200 ohms and the capacitance is 0.0001 Farad. Match each item to a choice: Solve for the current "i' at any time 't". Solve for the charge "q" at any time "t'. Choices: # none of these i(t) = 0.25e-50t i(t) = -0.50e-50t i(t) = -0.= -1 1 (10 – e-50t) (10+ e¬60t) 103 i(t) = 0.50 q(t) 9(t) = 100 ; ! none of these 1 q(t) = (1 – e-30*) 10 :::

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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An R-C series circuit has a supply voltage of 100 V. The resistance is 200 ohms and the capacitance is 0.0001 Farad. Match each item to a choice: Solve for the current "i" at any time "t". Solve for the charge "q" at any time "t". Choices: -50t : none of these - 50t - 50t :: :: i(t) = 0.25e i(t) = -0.50e i(t) = -0.25e -1 1 -50t 1 :: i(t) = 0.50e q(t) (10 100 -50t) 9(t) J0 :(10+e-50t) 103 q(t) =(1 - e-60t) 100 - e E none of these q(t) = 10
Transcribed Image Text:An R-C series circuit has a supply voltage of 100 V. The resistance is 200 ohms and the capacitance is 0.0001 Farad. Match each item to a choice: Solve for the current "i" at any time "t". Solve for the charge "q" at any time "t". Choices: -50t : none of these - 50t - 50t :: :: i(t) = 0.25e i(t) = -0.50e i(t) = -0.25e -1 1 -50t 1 :: i(t) = 0.50e q(t) (10 100 -50t) 9(t) J0 :(10+e-50t) 103 q(t) =(1 - e-60t) 100 - e E none of these q(t) = 10
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