An owl is carrying a mouse to the chicks in its nest. It is 4.00 m west and 12.0 m above the center of the 30 cm diameter nest and is flying east at 4.50 m/s at an angle 34° below the horizontal when it accidentally drops the mouse. Will it fall into the nest? Find out by solving for the horizontal position of the mouse (measured from the point of release) when it has fallen the 12.0 m. m (from the point of release)
An owl is carrying a mouse to the chicks in its nest. It is 4.00 m west and 12.0 m above the center of the 30 cm diameter nest and is flying east at 4.50 m/s at an angle 34° below the horizontal when it accidentally drops the mouse. Will it fall into the nest? Find out by solving for the horizontal position of the mouse (measured from the point of release) when it has fallen the 12.0 m. m (from the point of release)
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:**Problem Description:**
An owl is carrying a mouse to the chicks in its nest. It is 4.00 meters west and 12.0 meters above the center of the 30 cm diameter nest. The owl is flying east at a velocity of 4.50 m/s at an angle of 34° below the horizontal when it accidentally drops the mouse. Determine if the mouse will fall into the nest by solving for the horizontal position of the mouse (measured from the point of release) when it has fallen 12.0 meters.
**Solution Steps:**
1. **Understand the Initial Conditions:**
- Initial horizontal distance from the nest: 4.00 meters west.
- Initial vertical height above the center of the nest: 12.0 meters.
- Velocity of the owl: 4.50 m/s at a 34° angle below the horizontal.
2. **Calculate Horizontal and Vertical Components of Velocity:**
- Horizontal component (\(V_{x0}\)): \(4.50 \cos(34°)\)
- Vertical component (\(V_{y0}\)): \(4.50 \sin(34°)\)
3. **Analyze the Vertical Motion:**
- Using the equation of motion: \(y = V_{y0}t + \frac{1}{2}gt^2\)
- The mouse drops vertically 12.0 meters, solve for time (\(t\)).
4. **Analyze the Horizontal Motion:**
- Using uniform motion equation: \(x = V_{x0}t\)
- Solve for horizontal position (\(x\)).
5. **Determine if it Falls into the Nest:**
- Check if the horizontal position after falling 12.0 meters aligns with the nest (consider nest’s diameter).
**Details:**
The nest has a diameter of 30 cm (0.30 meters), which means for the mouse to fall into the nest, its horizontal position must be within ±0.15 meters from the center point when falling.
**Conclusion:**
Complete the calculation to find the horizontal displacement from the point of release to ascertain whether the mouse lands within the nest's boundary.
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