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An oscillator circuit is important to many applications. A simple oscillator circuit can be built by adding a neon gas tube to an RC circuit, as shown in the figure (Figure 1). Gas is normally a good insulator, and the resistance of the gas tube is essentially infinite when the light is off. This allows the capacitor to charge. When the capacitor voltage reaches a value Von, the electric field inside the tube becomes strong enough to ionize the neon gas. Visually, the tube lights with an orange glow. Electrically, the ionization of the gas provides a very-low-resistance path through the tube. The capacitor very rapidly (we can think of it as instantaneously) discharges through the tube and the capacitor voltage drops. When the capacitor voltage has dropped to a value Voff, the electric field inside the tube becomes too weak to sustain the ionization and the neon light turns off. The capacitor then starts to charge again. The capacitor voltage oscillates between Voff, when it starts charging, and Von, when the light comes on to discharge it. Part B A neon gas tube has Von = 40.0 V and Voff = 20.0 V. What resistor value should you choose to go with a 10.0 uF capacitor and a 120 V battery to make a 30.0 Hz oscillator? Express your answer in ohms. ΜΕ ΑΣΦ ? Ω Figure + AVC E- Von Voff 0 R ww Neon gas tube 1 of 1 Submit Previous Answers Request Answer × Incorrect; Try Again; 4 attempts remaining < Return to Assignment Provide Feedback

An oscillator circuit is important to many applications. A simple oscillator circuit can be built by adding a neon gas tube to an RC circuit, as shown in the figure (Figure 1). Gas is normally a good insulator, and the resistance of the gas tube is essentially infinite when the light is off. This allows the capacitor to charge. When the capacitor voltage reaches a value Von, the electric field inside the tube becomes strong enough to ionize the neon gas. Visually, the tube lights with an orange glow. Electrically, the ionization of the gas provides a very-low-resistance path through the tube. The capacitor very rapidly (we can think of it as instantaneously) discharges through the tube and the capacitor voltage drops. When the capacitor voltage has dropped to a value Voff, the electric field inside the tube becomes too weak to sustain the ionization and the neon light turns off. The capacitor then starts to charge again. The capacitor voltage oscillates between Voff, when it starts charging, and Von, when the light comes on to discharge it. Part B A neon gas tube has Von = 40.0 V and Voff = 20.0 V. What resistor value should you choose to go with a 10.0 uF capacitor and a 120 V battery to make a 30.0 Hz oscillator? Express your answer in ohms. ΜΕ ΑΣΦ ? Ω Figure + AVC E- Von Voff 0 R ww Neon gas tube 1 of 1 Submit Previous Answers Request Answer × Incorrect; Try Again; 4 attempts remaining < Return to Assignment Provide Feedback

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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An oscillator circuit is important to many applications. A simple oscillator circuit can be built by adding a neon gas tube to an RC circuit, as shown in the figure (Figure 1). Gas is normally a good insulator, and the resistance of the gas tube is essentially infinite when the light is off. This allows the capacitor to charge. When the capacitor voltage reaches a value Von, the electric field inside the tube becomes strong enough to ionize the neon gas. Visually, the tube lights with an orange glow. Electrically, the ionization of the gas provides a very-low-resistance path through the tube. The capacitor very rapidly (we can think of it as instantaneously) discharges through the tube and the capacitor voltage drops. When the capacitor voltage has dropped to a value Voff, the electric field inside the tube becomes too weak to sustain the ionization and the neon light turns off. The capacitor then starts to charge again. The capacitor voltage oscillates between Voff, when it starts charging, and Von, when the light comes on to discharge it. Part B A neon gas tube has Von = 40.0 V and Voff = 20.0 V. What resistor value should you choose to go with a 10.0 uF capacitor and a 120 V battery to make a 30.0 Hz oscillator? Express your answer in ohms. ΜΕ ΑΣΦ ? Ω Figure + AVC E- Von Voff 0 R ww Neon gas tube 1 of 1 Submit Previous Answers Request Answer × Incorrect; Try Again; 4 attempts remaining < Return to Assignment Provide Feedback
Transcribed Image Text:An oscillator circuit is important to many applications. A simple oscillator circuit can be built by adding a neon gas tube to an RC circuit, as shown in the figure (Figure 1). Gas is normally a good insulator, and the resistance of the gas tube is essentially infinite when the light is off. This allows the capacitor to charge. When the capacitor voltage reaches a value Von, the electric field inside the tube becomes strong enough to ionize the neon gas. Visually, the tube lights with an orange glow. Electrically, the ionization of the gas provides a very-low-resistance path through the tube. The capacitor very rapidly (we can think of it as instantaneously) discharges through the tube and the capacitor voltage drops. When the capacitor voltage has dropped to a value Voff, the electric field inside the tube becomes too weak to sustain the ionization and the neon light turns off. The capacitor then starts to charge again. The capacitor voltage oscillates between Voff, when it starts charging, and Von, when the light comes on to discharge it. Part B A neon gas tube has Von = 40.0 V and Voff = 20.0 V. What resistor value should you choose to go with a 10.0 uF capacitor and a 120 V battery to make a 30.0 Hz oscillator? Express your answer in ohms. ΜΕ ΑΣΦ ? Ω Figure + AVC E- Von Voff 0 R ww Neon gas tube 1 of 1 Submit Previous Answers Request Answer × Incorrect; Try Again; 4 attempts remaining < Return to Assignment Provide Feedback
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