An orthogonal cutting operations is being carried out in which uncut thickness is 0.010 mm, cutting speed is 130 m/min, rake angle is 15° and width of cut is 6 mm. It is observed that the chip thickness is 0.015 mm, the cutting force is 60 N and the thrust force is 25 N. The ratio of friction energy to total energy is (correct to two
An orthogonal cutting operations is being carried out in which uncut thickness is 0.010 mm, cutting speed is 130 m/min, rake angle is 15° and width of cut is 6 mm. It is observed that the chip thickness is 0.015 mm, the cutting force is 60 N and the thrust force is 25 N. The ratio of friction energy to total energy is (correct to two
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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Find the ratio of friction energy to total energy,i need correct solution without any mistakes otherwise skip to others
![An orthogonal cutting operations is being carried out in which uncut thickness is 0.010
mm, cutting speed is 130 m/min, rake angle is 15° and width of cut is 6 mm. It is
observed that the chip thickness is 0.015 mm, the cutting force is 60 N and the thrust
force is 25 N. The ratio of friction energy to total energy is
(correct to two](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9c659418-d93a-45ae-9d0b-ad98426d4564%2Fb26d9905-923e-42ce-a209-e95cbfa58f87%2Ftb9f5yl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:An orthogonal cutting operations is being carried out in which uncut thickness is 0.010
mm, cutting speed is 130 m/min, rake angle is 15° and width of cut is 6 mm. It is
observed that the chip thickness is 0.015 mm, the cutting force is 60 N and the thrust
force is 25 N. The ratio of friction energy to total energy is
(correct to two
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