An orange grower is introducing a new variety of orange. The grower claims that the new oranges have a mean pH of 5. To test the claim, an independent researcher chose a random sample of 22 of the new oranges, finding they had a sample mean pH of 5.1 with a sample standard deviation of 0.8. Assume that the population of pH values of the new oranges is approximately normally distributed. Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.10 level of significance, to reject the claim that u, the mean pH of the new oranges, is 5. (a) State the null hypothesis H and the alternative hypothesis H, that you would use for the test. Ho: 0 H: 0 O

Q: Solve for X. X = (21-×3-1 5 = I.

A: Given that

Q: Solve -5 + 7,I +6 = 37 for a

A:

Q: How do I solve these

A:

Q: 2х — 6 < 2 1 —х

A: topic - inequality

Q: Solve for x. 2x - 2, x +5

A:

Q: Solve. 3m-3= - 19+m

A:

Q: |2х +3 3 13

A:

Q: solve for b a=1\2bh

A: We will find the value of b in terms of a and h as following .

Q: 4. -8z -y+3: =1 4r + 4y +== 41 6r + 4y + 7: = 114 5. 3r + 7y - 2: = 37 6r + 7y + 10: = 46 -v+ 2: =-4

A: 4) Given:

Q: solve, d,e,f

A: Given, the quarterly sales of the TRK-50 mountain bike for the previous four years by a bicycle shop…

Q: 16 a

A: topic - similar triangles

Q: Find the value of the determinant. |-2 -4 -4 3 -1 -2 2 2-5

A:

Q: Solve for VW

A: Use the Pythagoras theorem as there is a right-angled triangle present in the circle, use the…

Q: Solve number 2

A:

Q: solve yiv + 2y" = 0

A:

Q: 3. 3r+ Sy - 2: = 52 4r+ 7y +a= SI -2r- 9y + Sa--53

A:

Equations and Inequations

Equations and inequalities describe the relationship between two mathematical expressions.

Linear Functions

A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.