An optical instrument uses an objective lens of power 100 D and an eyepiece of power 40 D. The final image is formed at infinity when the tube length of the instrument is kept at 20 cm. (a) Identify the optical instrument. (b) Calculate the angular magnification produced by the instrument.
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- 1) Calculate the magnification of the 36-in refractor at Lick Observatory on Mount Hamilton near San Jose, California. The focal lenght of the objective lens is 17.37m, and the focal lenght of the eyepiece is 22 mm. (Express your answer to three significant figures.) 2) What is the significance of the negative sign in the magnification equation? a) The image is inverted when viewed in the eyepiece. b) The image is upright when viewed in the eyepiece.Assume that the near point of a hyperopic (farsighted) eye is 0.936 m in front of the eye. A lens is used to let the eye see clearly an object that is 0.250 m in front of the eye. Ignore the small distance from the lens to the eye. What is the power of the lens (in diopters; answer sign and magnitude)?Is this question set up wrong? I think the statement "The magnification of a book held 7.50 cm from a 10.0 cm-focal length lens is 3.00." is impossible using the lens equation 1/do + 1/di = 1/f and the equation for magnification m = -di / do.
- A person sees clearly wearing eyeglasses that have a power of −2.00 diopters when the lenses are 2.30 cm in front of the eyes. (a) What is the focal length of the lens? cm(b) Is the person nearsighted or farsighted? nearsightedfarsighted (c) If the person wants to switch to contact lenses placed directly on the eyes, what lens power should be prescribed? dioptersNeeds Complete solution with 100 % accuracy.People who do very detailed work close up, such as jewellers, often can see objects clearly at much closer distance than the normal 25 cm. (a) What is the power in D of the eyes of a woman who can see an object clearly at a distance of only 7.30 cm? (Assume the lens-to-retina distance is 2.00 cm.) ____D (b) What is the size in mm of an image of a 6.00 mm object, such as lettering inside a ring, held at this distance? (Include the sign of the value in your answer.) ______mm (c) What would the size of the image be in mm if the object were held at the normal 25.0 cm distance? (Include the sign of the value in your answer.) _____mm
- An individual is nearsighted; his near point is 15.0 cm and his far point is 47.0 cm. (a) What lens power is needed to correct his nearsightedness? -2.13 diopters (b) When the lenses are in use, what is this person's near point? -0.469 x cm(part 1 of 3) A person with a nearsighted eye has near and far points of 10 cm and 23 cm, respectively. Assuming a lens is placed 2.7 cm from the eye, what power must the lens have to correct this condition? Answer in units of diopter. (part 2 of 3) Contact lenses placed directly on the cornea are used to correct the eye. What is the power of the lens required in this case? Answer in units of diopter. (part 3 of 3) 1 What is the new near point? Answer in units of cm.Problem 12: A student wears eyeglasses of power P = -3.75 diopter to correct nearsightedness. The glasses are designed to be worn d = 1.3 cm in front of the eye. Part (a) Input an expression for the far point the student can see without correction, do. Part (b) Numerically, what is the distance in meters?