An optical inspection system is used to distinguish among different part types. Suppose that three parts are inspected and that the classifications are independent. Let the random variable X denote the number of parts that are correctly classified. The probability mass function is given below. Determine the mean and variance of the random variable. P(X=0) 0.000008 P(X=1) 0.001176 P(X=2) 0.057624 P(X=3) 0.941192 Оа. и 3 Е(X) — 2.94 o2 = V (X) = 0.00346 Ob. µ = E(X) = 2.94 o² = V (X) = 0.0588 О с. и 3D Е(X) — 2.94 o2 = V (X) = 8.7024 O d. None among the choices
An optical inspection system is used to distinguish among different part types. Suppose that three parts are inspected and that the classifications are independent. Let the random variable X denote the number of parts that are correctly classified. The probability mass function is given below. Determine the mean and variance of the random variable. P(X=0) 0.000008 P(X=1) 0.001176 P(X=2) 0.057624 P(X=3) 0.941192 Оа. и 3 Е(X) — 2.94 o2 = V (X) = 0.00346 Ob. µ = E(X) = 2.94 o² = V (X) = 0.0588 О с. и 3D Е(X) — 2.94 o2 = V (X) = 8.7024 O d. None among the choices
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:An optical inspection system is used to distinguish among different part types. Suppose that
three parts are inspected and that the classifications are independent. Let the random variable
X denote the number of parts that are correctly classified. The probability mass function is
given below. Determine the mean and variance of the random variable.
P(X=0)
0.000008
P(X=1)
0.001176
P(X=2)
0.057624
P(X=3)
0.941192
Оа. и 3 Е(X) — 2.94
o2 = V (X) = 0.00346
Ob.
µ = E(X) = 2.94
o² = V (X) = 0.0588
О с. и 3D Е(X) — 2.94
o2 = V (X) = 8.7024
O d. None among the choices
Transcribed Image Text:Errors in an experimental transmission channel are found when the transmission is checked by
a certifier that detects missing pulses. The number of errors found in an eight-bit byte is a
random variable with the following distribution. Determine P(X < 4)
x<1
0.7
1<x< 4
F(x) =
|0.9
4<x<7
7< x
O a. 0.70
O b.0.90
O c. 0.20
O d. None among the choices
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