An opening in a floor is covered by a 1 x 1.2-m sheet of plywood with a mass of 18 kg. The sheet is hinged at A and B and is maintained in a position slightly above the floor by a small block C. Determine the vertical component of the reaction (a) at A, (b) at B, (c) at C. 0.2 m 0.6 m 1.2 m 0.2 m E 0.15 m

Q: Find the reactions at points A and B: 4 * A F=goolb. + 5 F=750lb 2-6" 5" 9=45010 1 B +

A: Objective: To determine the reactions at point A and B.   The free body diagram of the given…

Q: A smooth sphere of 2 kN weight and 2 cm radius is resting against the walls as shown in figure.…

A: Given Data,For a smooth sphere,Weight, w= 2kNTo find the reactions at the supporting points

Q: Roller -4 ft 4 ft 2 ft- 3. Determine the reaction components at the sup shown. (10 points) 6 kN/m B…

A:

Q: Determine the reactions at A and B for the steel bar and loading shown, assuming a close fit at both…

A: Given data:- Conditions given-Remove restriction at A and solve for the reactions Below bar figure…

Q: Let P = [P] N. m) Determine the magnitude FA of the reaction at pin A. n) Determine the magnitude FB…

A:

Q: Calculate the following: 1. Calculate the reaction at D: RD = kN answer in absolute value and 3…

A: Given: Required: Reaction at roller D Horizontal reaction at E Vertical reaction at E Note: As…

Q: Problem #3: X (N) B A (m) 2 m - - 2 m- A 60° 11. Determine the horizontal reaction at A. (N) 12.…

A:

Q: E 20 k 12 ft 12 ft 5 k -5 ft-5 ft- -14 ft-

A:

Q: Determine the reaction at the support B. 500 N 400 N 0,5 m 2 m 2 m

A: Since the system is in equilibrium, hence Net force in x and y directions are zero also, net moment…

Q: Problem #2: Y (N) 2 m C (m) B X (N) 1 m 2.5 m D 2 m 13. Determine the horizontal reaction at A. (N)…

A:

Q: Determine the reaction at the support B. 500 N 400 N 0.5 m B 2 m 2 m

A:

Q: The beam has an internal hinge at C. Express your answers in kN. 5 kN 3 kN/m 3m 3 m 11.5m 1.5 m…

A:

Q: Determine the Reaction at A and the member BE in the fig below.

A:

Q: 18 Because of long-term loading from the 900-N tension in the power line, the uniform utility pole…

A:

Q: 2 Compute the internal reaction of member DG of the truss. F D B = 60 KN 80 KN 14 m B A J 4 m C 4 m…

A:

Q: Problem #1: в (m) 800 + A (N) 200 + Y (N/m) 2 m \60° B 1. Determine the horizontal reaction at A.…

A: 1. Determine the horizontal reaction at A. 2. Determine the vertical reaction at A.  3. Determine…

Q: me the reactions at the supports. - 4 m 500 N/m 30 4 m

A:

Q: c) Calculate the vertical reaction at support B. When sketching FBD, assume the positive direction…

A:

Q: Determine the reactions at A, F, and E. 0.5 m E C 0.5 m 200 N B 0.8 m 0.6 m 2 m

A:

Q: From the figure below, determine reaction Ch

A: Support reaction: Apply equilibrium condition ∑MC=0AV×8-45×4=0AV=22.5 KN∑FY=0AV+CV=022.5…

Q: A hollow steel tube (1) with an outside diameter of D1 and a wall thickness of t1 is connected to a…

A: E1 = 210 GPaE2 = E3 = 55 GPa Determinea. The movement of joint B with respect to support A. b. The…

Q: Solve for the reaction at B.

A: This question has been taken from structural analysis

Q: 1 Compute the internal reaction of member FH of the truss. F D B = 60 KN 80 KN 14 m B A J 4 m C 4 m…

A:

Q: Vertical reaction at roller A in kN. RA Vertical reaction at roller C in kN. RC

A:

Q: D FAS determine the reactions at roller C 10 kN/m 2m B 9 kN 4m 1.5m -

A:

Q: 2 -6 ft- 10 k/ft 12 ft $300 -6 ft- B

A:

Q: The truss shown in the figure is supported on a roller at B and a hinge at A. Solve for the reaction…

A:

Q: Determine the vertical and horizontal components of the reaction at pinned C and A.

A:

System of Forces

A force is an external influence or agent that changes the state of a system. According to Newton's second law, the force applied to a body is proportional to the change in momentum of a body. Hence, whenever a force is applied to a body, its momentum changes. If the body is at rest, under the action of force, its state of rest changes to motion. In other words, the magnitude of the momentum of the body changes from zero to a measurable value. Similarly, if the body possesses some initial velocity, it has some associated momentum, the effect of force can cause the body to halt or come to rest, that is, the momentum reduces to zero.