An open top rectangular tank with square bases is to have a volume of 10 cu. m. The materials for its bottom are to cost P 15 per square meter and that for the sides, P6 per square meter. Find the most economical dimensions for the tank. A. B. 1.5m x 1.5m x 4.4m 2m x 2m x 2.5m C. 4m x 4m x 0.6m D. 3m x 3m x 1.1m What is the maximum profit when the profit-versus-production function is as given below? P is profit and x is unit of production. P=200,00-x- A. 285,000 B. 200,000 C. 250,000
An open top rectangular tank with square bases is to have a volume of 10 cu. m. The materials for its bottom are to cost P 15 per square meter and that for the sides, P6 per square meter. Find the most economical dimensions for the tank. A. B. 1.5m x 1.5m x 4.4m 2m x 2m x 2.5m C. 4m x 4m x 0.6m D. 3m x 3m x 1.1m What is the maximum profit when the profit-versus-production function is as given below? P is profit and x is unit of production. P=200,00-x- A. 285,000 B. 200,000 C. 250,000
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:An open top rectangular tank with
square bases is to have a volume of 10 cu.
m. The materials for its bottom are to cost
P 15 per square meter and that for the
sides, P6 per square meter. Find the most
economical dimensions for the tank.
A.
B.
C.
D.
1.5m x 1.5m x 4.4m
2m x 2m x 2.5m
4m x 4m x 0.6m
3m x 3m x 1.1m
What is the maximum profit when the
profit-versus-production function is as
given below? P is profit and x is unit of
production.
P=200,00-x-
A. 285,000
B. 200,000
C. 250,000
1.1
X+1
Transcribed Image Text:The cost of fuel in running a locomotive is
proportional to the square of the speed
and is $ 25 per hour for a speed of 25
miles per hour. Other costs amount to S
100 per hour, regardless of the speed.
What is the speed which will make the cost
per mile a minimum?
A. 40
B. 55
C. 50
D. 45
The cost C of a product is a function of the
quantity x of the product: C(x)=x²-4000
x+50. Find the quantity for which the cost
is minimum.
A. 1000
B. 1500
C. 2000
D. 3000
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