An open box of maximum volume is to be made from a square piece of material, s = 30 inches on a side, by cutting equal squares from the corners and turning up the sides (see fi X (a) Analytically complete six rows of a table such as the one below. (The first two rows are shown.) Length and Width Volume, V 1[302(1)]2= 784 30 - 2(1) 30 2(2) 2[302(2)]²= 1352 302(3) 3[302(3)]²= 4 302(4) 4[30-2(4)]²= 5 302(5) 5[302(5)]²= 30-2(6) 6[302(6)]²=| Height, x V = 1 2 3 s-2x- 6 Use the table to guess the maximum volume. V = (b) Write the volume V as a function of x. I 0 < x < 15 (c) Use calculus to find the critical number of the function in part (b) and find the maximum value. V= (d) Use a graphing utility to graph the function in part (b) and verify the maximum volume from the graph.

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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An open box of maximum volume is to be made from a square piece of material, s = 30 inches on a side, by cutting equal squares from the corners and turning up the sides (see figure).
2x
X
V =
(a) Analytically complete six rows of a table such as the one below. (The first two rows are shown.)
Length and
Width
30 - 2(1)
30 - 2(2)
30 2(3)
30 - 2(4)
Height, x
1
2
3
4
5
6
s-2x-
30 - 2(5)
30 - 2(6)
X
I
Volume, V
1[30 – 2(1)]² = 784
2[30 – 2(2)]² = 1352
3[30 – 2(3)]² =
=
Use the table to guess the maximum volume.
V =
(b) Write the volume V as a function of x.
4[30 – 2(4)]² :
=
5[30 – 2(5)]²=
6[30 – 2(6)]² =
0 < x < 15
=
(c) Use calculus to find the critical number of the function in part (b) and find the maximum value.
V =
(d) Use a graphing utility to graph the function in part (b) and verify the maximum volume from the graph.
Transcribed Image Text:An open box of maximum volume is to be made from a square piece of material, s = 30 inches on a side, by cutting equal squares from the corners and turning up the sides (see figure). 2x X V = (a) Analytically complete six rows of a table such as the one below. (The first two rows are shown.) Length and Width 30 - 2(1) 30 - 2(2) 30 2(3) 30 - 2(4) Height, x 1 2 3 4 5 6 s-2x- 30 - 2(5) 30 - 2(6) X I Volume, V 1[30 – 2(1)]² = 784 2[30 – 2(2)]² = 1352 3[30 – 2(3)]² = = Use the table to guess the maximum volume. V = (b) Write the volume V as a function of x. 4[30 – 2(4)]² : = 5[30 – 2(5)]²= 6[30 – 2(6)]² = 0 < x < 15 = (c) Use calculus to find the critical number of the function in part (b) and find the maximum value. V = (d) Use a graphing utility to graph the function in part (b) and verify the maximum volume from the graph.
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An open box of maximum volume is to be made from a square piece of material, s = 30 inches on a side, by cutting equal squares from the corners and turning up the sides.

let the length of the sides of the square corners cut be x inches.

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