An oil spill is the shape of a thin cylinder which is constantly 2 cm thick and is expanding. The volume of the spill is increasing by 30 cm^3 /sec. How fast is the radius increasing when the radius of the spill is 200 cm? The volume of a cylinder of heigh h and radius r is V= pi *r^2 *h Solution = _________
An oil spill is the shape of a thin cylinder which is constantly 2 cm thick and is expanding. The volume of the spill is increasing by 30 cm^3 /sec. How fast is the radius increasing when the radius of the spill is 200 cm? The volume of a cylinder of heigh h and radius r is V= pi *r^2 *h Solution = _________
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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An oil spill is the shape of a thin cylinder which is constantly 2 cm thick and is expanding. The volume of the spill is increasing by 30 cm^3 /sec. How fast is the radius increasing when the radius of the spill is 200 cm? The volume of a cylinder of heigh h and radius r is V= pi *r^2 *h
Solution = _________
Expert Solution
Step 1
Let r and h, in cm be the radius and height of cylinder at any time t . Let V cm^3 be the volume of cylinder at any time t. Height of cylinder is constantly 2 cm, that is h=2cm.
Since, volume of the spill is increasing by 30 cm^3 /sec.
Therefore,
Step 2
Now, Volume of cylinder is
Substitute h=2 cm
When r=200 cm
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