**Problem Statement:**An oil pump is drawing 18 kW of electric power while pumping oil with a density of 860 kg/m³ at a rate of 0.1 m³/s. The inlet and outlet diameters of the pipe are 8 cm and 20 cm, respectively. If the pressure rise of oil in the pump is measured to be 250 kPa and the motor efficiency is 95 percent, determine the mechanical efficiency of the pump. Take the kinetic energy correction factor as 1.05.**Diagram Explanation:**- There is a side view of a pump and motor system.- To the left is the pump, marked as having an 8 cm diameter inlet.- Oil is entering the pump at a velocity corresponding to 0.1 m³/s and a density of 860 kg/m³.- The outlet of the pump has a larger diameter marked as 20 cm.- A motor is connected to the pump, drawing 18 kW of electric power, and has an efficiency of 95%.- The pressure rise is indicated as ΔP = 250 kPa. **Question:**Calculate the mechanical efficiency of the pump and enter the result in the blank provided (%).

Answered: Image /qna-images/answer/cc494c80-1176-40af-aa6d-bb7a66cb956e.jpg

An oil pump is drawing 18 kW of electric power while pumping oil with density 860 kg/m3 at a rate of 0.1 m3/s. The inlet and outlet diameters of the pipe are 8 cm and 20 cm, respectively. If the pressure rise of oil in the pump is measured to be 250 kPa and the motor efficiency is 95 percent, determine the mechanical efficiency of the pump. Take the kinetic energy correction factor as 1.05. 18 kW Docm Pump Motor 8 сm Oil AP = 250 kPa 0.1 m/s The mechanical efficiency of the pump is |%.

An oil pump is drawing 18 kW of electric power while pumping oil with density 860 kg/m3 at a rate of 0.1 m3/s. The inlet and outlet diameters of the pipe are 8 cm and 20 cm, respectively. If the pressure rise of oil in the pump is measured to be 250 kPa and the motor efficiency is 95 percent, determine the mechanical efficiency of the pump. Take the kinetic energy correction factor as 1.05. 18 kW Docm Pump Motor 8 сm Oil AP = 250 kPa 0.1 m/s The mechanical efficiency of the pump is |%.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Sediment transport

Sediment transport or Soil transport is the movement of solid particles, usually due to the combination of gravitational forces acting on the sediment, and the movement of the liquid at which the sediment enters. Soil erosion occurs in natural systems where the particles are sandstones (sand, rocks), mud, or clay; the liquid is air, water, or ice; and the gravitational force that works to move particles to the landing surface. Sediment transportation or soil migration due to the movement of liquids occurs in rivers, lakes, lakes, oceans, and other bodies of water as a result of currents and waves. Transportation is also caused by glaciers as they flow, and to places on earth under the influence of wind. Soil erosion due to gravity alone is possible in most sloping areas, including hills, scarves, cliffs, and the continental shelf — the continental boundary of the slope.

Question

**Problem Statement:**

An oil pump is drawing 18 kW of electric power while pumping oil with a density of 860 kg/m³ at a rate of 0.1 m³/s. The inlet and outlet diameters of the pipe are 8 cm and 20 cm, respectively. If the pressure rise of oil in the pump is measured to be 250 kPa and the motor efficiency is 95 percent, determine the mechanical efficiency of the pump. Take the kinetic energy correction factor as 1.05.

**Diagram Explanation:**

- There is a side view of a pump and motor system.
- To the left is the pump, marked as having an 8 cm diameter inlet.
- Oil is entering the pump at a velocity corresponding to 0.1 m³/s and a density of 860 kg/m³.
- The outlet of the pump has a larger diameter marked as 20 cm.
- A motor is connected to the pump, drawing 18 kW of electric power, and has an efficiency of 95%.
- The pressure rise is indicated as ΔP = 250 kPa.

**Question:**

Calculate the mechanical efficiency of the pump and enter the result in the blank provided (%).

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