An October 2011 CBS News Poll on illegal immigrants interviewed 1012 randomly selected American adults. Of those in the sample, 688 said that they “oppose allowing the children of illegal immigrants to attend state college at the lower tuition rate of state residents.” Although the samples in national polls are not SRSs, they are similar enough that our method gives approximately correct confidence intervals. Find the 99% confidence interval for the proportion of adults who “oppose allowing the children of illegal immigrants to attend state college at the lower tuition rate of state residents.” Interpret the confidence interval in a clear sentence.Find the 95% confidence interval. Is the 95% confidence interval longer or shorter than the 99% confidence interval? Find the margin of error for each confidence interval. (Hint: you do have enough information from the calculator output! Margin of error = (width of interval)/2.) Margin of error for 99% confidence interval: Margin of error for 95% confidence interval:

Givensample size(n)=1012x=688p^=xn=6881012=0.6798

Answered: An October 2011 CBS News Poll on…

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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An October 2011 CBS News Poll on illegal immigrants interviewed 1012 randomly selected American adults. Of those in the sample, 688 said that they “oppose allowing the children of illegal immigrants to attend state college at the lower tuition rate of state residents.” Although the samples in national polls are not SRSs, they are similar enough that our method gives approximately correct confidence intervals.

Find the 99% confidence interval for the proportion of adults who “oppose allowing the children of illegal immigrants to attend state college at the lower tuition rate of state residents.” Interpret the confidence interval in a clear sentence.

Find the 95% confidence interval. Is the 95% confidence interval longer or shorter than the 99% confidence interval?

Find the margin of error for each confidence interval. (Hint: you do have enough information from the calculator output! Margin of error = (width of interval)/2.)

Margin of error for 99% confidence interval:

Margin of error for 95% confidence interval:

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