An object 1.55 cm1.55 cm tall is placed 3.20 cm in front of a spherical concave mirror with a radius of curvature equal to 11.2 cm. In the diagrams, the solid arrow represents the object, whereas the dashed arrow represents the image.

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An object 1.55 cm1.55 cm tall is placed 3.20 cm in front of a spherical concave mirror with a radius of curvature equal to 11.2 cm.

In the diagrams, the solid arrow represents the object, whereas the dashed arrow represents the image.

 

Calculate the image distanceI dI. (cm)

Calculate the image height hI. (cm)

**Select the correct ray diagram.**

There are four ray diagrams depicted, each with a concave mirror and lines illustrating the path of light rays:

1. **Top Left Diagram:**
   - The principal axis is a straight horizontal line.
   - The object is placed in front of the mirror.
   - Light rays are shown traveling towards the mirror:
     - One ray passes parallel to the principal axis, reflects through the focal point (F).
     - Another ray passes through F and reflects parallel to the principal axis.
   - The intersection of reflected rays behind the mirror indicates the location of the image.

2. **Top Right Diagram:**
   - A similar setup with the principal axis and the concave mirror.
   - Light rays:
     - One is parallel to the principal axis, reflecting through the focal point (F).
     - Another passes through the center of curvature (C) and retraces its path.
   - Ray intersection forms the image on the same side as the object.

3. **Bottom Left Diagram:**
   - Again, the principal axis with the concave mirror.
   - Rays:
     - One parallel to the principal axis, reflecting through F.
     - Another through the center of curvature (C), reflecting back on itself.
   - The image appears between C and F on the object side.

4. **Bottom Right Diagram:**
   - Principal axis with a ray parallel to it, reflecting through F.
   - Another set of rays through mirror interactions.
   - Rays converge on the image side of the principal axis.

**Calculate the image distance, \( d_i \).**

(Note: This problem likely involves using the mirror equation \(\frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i}\), where \( f \) is the focal length, \( d_o \) is the object distance, and \( d_i \) is the image distance.)
Transcribed Image Text:**Select the correct ray diagram.** There are four ray diagrams depicted, each with a concave mirror and lines illustrating the path of light rays: 1. **Top Left Diagram:** - The principal axis is a straight horizontal line. - The object is placed in front of the mirror. - Light rays are shown traveling towards the mirror: - One ray passes parallel to the principal axis, reflects through the focal point (F). - Another ray passes through F and reflects parallel to the principal axis. - The intersection of reflected rays behind the mirror indicates the location of the image. 2. **Top Right Diagram:** - A similar setup with the principal axis and the concave mirror. - Light rays: - One is parallel to the principal axis, reflecting through the focal point (F). - Another passes through the center of curvature (C) and retraces its path. - Ray intersection forms the image on the same side as the object. 3. **Bottom Left Diagram:** - Again, the principal axis with the concave mirror. - Rays: - One parallel to the principal axis, reflecting through F. - Another through the center of curvature (C), reflecting back on itself. - The image appears between C and F on the object side. 4. **Bottom Right Diagram:** - Principal axis with a ray parallel to it, reflecting through F. - Another set of rays through mirror interactions. - Rays converge on the image side of the principal axis. **Calculate the image distance, \( d_i \).** (Note: This problem likely involves using the mirror equation \(\frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i}\), where \( f \) is the focal length, \( d_o \) is the object distance, and \( d_i \) is the image distance.)
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