An object with a mass of 8.00 g is moving to the right at 14.0 cm/s when it is overtaken by an object with a mass of 25.0 g moving in the same direction with a speed of 17.0 cm/s. If the collision is elastic, determine the speed of each object after the collision in centimeters per second. v cm/s x cm/s 25.0 g object 15.55 8.00 g object 10.55

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### Physics Problem: Elastic Collision Example

#### Problem Statement:
An object with a mass of 8.00 g is moving to the right at 14.0 cm/s when it is overtaken by an object with a mass of 25.0 g moving in the same direction with a speed of 17.0 cm/s. If the collision is elastic, determine the speed of each object after the collision in centimeters per second.

#### Solution:
To solve the problem, we apply the principles of conservation of momentum and conservation of kinetic energy, which hold true for elastic collisions.

1. **Conservation of Momentum:**
   - Initial Momentum:
     \[ p_{initial} = m_1 * v_1 + m_2 * v_2 \]
     \[ p_{initial} = 8.00 \, \text{g} * 14.0 \, \text{cm/s} + 25.0 \, \text{g} * 17.0 \, \text{cm/s} \]
     \[ p_{initial} = 112.0 \, \text{g*cm/s} + 425.0 \, \text{g*cm/s} \]
     \[ p_{initial} = 537.0 \, \text{g*cm/s} \]

   - Final Momentum:
     \[ p_{final} = m_1 * v_{1f} + m_2 * v_{2f} \]
     \[ 537.0 = 8.00 * v_{1f} + 25.0 * v_{2f} \]

2. **Conservation of Kinetic Energy:**
   - Initial Kinetic Energy:
     \[ KE_{initial} = \frac{1}{2} * m_1 * v_1^2 + \frac{1}{2} * m_2 * v_2^2 \]
     \[ KE_{initial} = \frac{1}{2} * 8.00 * (14.0)^2 + \frac{1}{2} * 25.0 * (17.0)^2 \]
     \[ KE_{initial} = 784.0 + 3612.5 \]
     \[ KE_{initial} = 4396.5 \, \text{ergs} \]

   -
Transcribed Image Text:### Physics Problem: Elastic Collision Example #### Problem Statement: An object with a mass of 8.00 g is moving to the right at 14.0 cm/s when it is overtaken by an object with a mass of 25.0 g moving in the same direction with a speed of 17.0 cm/s. If the collision is elastic, determine the speed of each object after the collision in centimeters per second. #### Solution: To solve the problem, we apply the principles of conservation of momentum and conservation of kinetic energy, which hold true for elastic collisions. 1. **Conservation of Momentum:** - Initial Momentum: \[ p_{initial} = m_1 * v_1 + m_2 * v_2 \] \[ p_{initial} = 8.00 \, \text{g} * 14.0 \, \text{cm/s} + 25.0 \, \text{g} * 17.0 \, \text{cm/s} \] \[ p_{initial} = 112.0 \, \text{g*cm/s} + 425.0 \, \text{g*cm/s} \] \[ p_{initial} = 537.0 \, \text{g*cm/s} \] - Final Momentum: \[ p_{final} = m_1 * v_{1f} + m_2 * v_{2f} \] \[ 537.0 = 8.00 * v_{1f} + 25.0 * v_{2f} \] 2. **Conservation of Kinetic Energy:** - Initial Kinetic Energy: \[ KE_{initial} = \frac{1}{2} * m_1 * v_1^2 + \frac{1}{2} * m_2 * v_2^2 \] \[ KE_{initial} = \frac{1}{2} * 8.00 * (14.0)^2 + \frac{1}{2} * 25.0 * (17.0)^2 \] \[ KE_{initial} = 784.0 + 3612.5 \] \[ KE_{initial} = 4396.5 \, \text{ergs} \] -
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