An object of mass  M = 13.0 kg  is attached to a cord that is wrapped around a wheel of radius  r = 10.5 cm  (see figure). The acceleration of the object down the frictionless incline is measured to be  a = 2.00 m/s2  and the incline makes an angle  ? = 37.0°  with the horizontal. Assume the axle of the wheel to be frictionless

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A: According to Newton's second law F = ma We can use free body diagram to solve the problem. M1 = 490…

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A: To find-Speed of motor cyclist (V)=?Given-Angle of banking (θ)=210 49'Path length (l)=1 km=1000…

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A: N = Normal force on the car from surface M = Mass of the car g = Acceleration due to gravity = 9.8…

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A: To find-Maximum speed of car (V)=?Given data-mass of car (m)=800 kgRadius (r)=40 mCoefficient of…

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A: Given--- radius of planet = 5.4 times of the earth radius.  We have to find--- linear of a point…

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A: The expression for the required tension is,

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Q: The figure shows a conical pendulum, in which the bob (the small object at the lower end of the…

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A: in this question we use simple inertia equation and then angular motion equation.

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Q: An object of mass m=12kg is attached to a cord that is wrapped around a wheel of radius r=10cm.…

A: SOlution: Given that m = 12 kg r = 10 cm a = 2 m/s2 angle = 37

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A: diameter of the wheel = 10 m time taken to complete one revolution = 8 seconds weight of girl = 321…

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A: Mass (m) = 7 kg VA= 3.2 m/s  H=5.4 m  h =3.8 m RB= 4.2 m RC= 24 m.

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Centripetal Force

A particle, body, object or certain mass while travelling in a rotational path or semicircular path, experiences an inertia force. If that inertia force pulls the towards the inward of the imaginary circle in the rotation, it is termed as centripetal force.