An object of mass m is at rest on a smooth horizontal surface. It is pulled by a variable force F = kt, where t is the time. The force makes and angle a with the horizontal. a) find an expression for the speed of the object when it starts to lift-off the surface. b) find an expression for the distance travelled until it starts to lift-off the surface. a
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- A woman stands on a scale in a moving elevator. Her mass is 72.0 kg, and the combined mass of the elevator and scale is an additional 815 kg. Starting from rest, the elevator accelerates upward. During the acceleration, the hoisting cable applies a force of 9390 N. What does the scale read during the acceleration? NIf the child has a mass of 19.4 kg, calculate the magnitude of the force in newtons the mother exerts on the child under the following conditions. (b) The elevator accelerates upward at 0.762 m/s?. N Calculate the ratio of this force to the weight of the child. force child's weight (c) The elevator moves upward at a constant speed. Calculate the ratio of this force to the weight of the child. force child's weightd. Force is a vector quantity and thus has both a magnitude and a direction. A vector can be represented graphically by a line drawn to scale in the direction of the line of action of the force. To distinguish between vector and scalar quantities, various ways are used. Identify and explain threeof these ways.
- You are in a rocketship in deep space accelerating upwards with acceleration A. At the top of an inclined plane in the rocketship, you place a block of mass m. The length of the incline is L. If you let go of the block, what is the time taken by the block to reach the bottom of the incline? θ is the angle that the incline makes with the horizontal, and you make sure that the incline cannot move. Assume no friction.A cardboard box rests on the floor of an elevator. The box has a mass m = 2.75 kg and the elevator has an upward acceleration of a. a. Write an expression for the sum of the forces acting on the box in the y-direction, ΣFy, given that up is the positive y-direction. Your answer should be in terms of FN, m, and g. b. Write an expression for the normal force, FN, that the block experiences in terms of the elevator's acceleration, the block's mass, and the acceleration of gravity. c. If the elevator's acceleration has a magnitude of g in the downward direction, what would the normal force, FN1 be in Newtons? d.If the elevator's acceleration had a magnitude of g in the upward direction, what would the normal force FN2 be in Newtons?A teenager of mass m1 = 56 kg pushes backwards against the ground with his foot as he rides his skateboard. This exerts a horizontal force of magnitude F foot = = 18.5 N. The skateboard has m2 = 2.6 kg. a. Write an expression for the magnitude of the horizontal component of force that the ground exerts on the teenagers foot, F ground. b. Write an expression in terms to given quantities for the magnitude of the skateboard acceleration, a , while the teenager is pushing backwards on the ground? c. What is the numerical value of the magnitude of the acceleration, a, in m/s square?
- A 15.0 kg load of bricks hangs from one end of a rope that passes over a small, frictionless pulley. A 28.0 kg counter weight is attached to the other end of the rope, as shown in the figure. You may model the rope as a massless string. The system is released from rest. A. Draw two freebody diagrams, one for the load of bricks and one for the counter weight. B. Find the magnitude of the upward acceleration of the load of bricks. 28.0 kg C. What is the tension in the rope? D. How does the tension compare to the weight of the bricks and the weight of the counter weight? 15.0 kgNewton's first law states that: Group of answer choices Ia. n the absence of any net force acting on it, a mechanical system is necessarily at rest. b. In the absence of a non-zero net force acting on it, a mechanical system keeps moving in the same direction at the same speed (including the case v=0). c. For any pair A/B of objects interacting with one another, the force of A acting on B is the equal-opposite of the force of B acting on A. d. The rate of change of the velocity of a system is proportional to the net force acting on it.