An object of mass m falls from rest, starting at a point near the eart's surface. Assuming that the air resistance is proportional to the velocity magnitude of the object. k(resistance coefficient), m(mass), g(gravity) are positive constants. Find the velocity of the object in the form of t. what is the differantial equation to solve this problem? dV =g- dt dV mv² =g+ k II → dt k dV = m – –V² dt III → - - dV k g--V dt IV → %3D m V → dV = mg – kV -
An object of mass m falls from rest, starting at a point near the eart's surface. Assuming that the air resistance is proportional to the velocity magnitude of the object. k(resistance coefficient), m(mass), g(gravity) are positive constants. Find the velocity of the object in the form of t. what is the differantial equation to solve this problem? dV =g- dt dV mv² =g+ k II → dt k dV = m – –V² dt III → - - dV k g--V dt IV → %3D m V → dV = mg – kV -
An object of mass m falls from rest, starting at a point near the eart's surface. Assuming that the air resistance is proportional to the velocity magnitude of the object. k(resistance coefficient), m(mass), g(gravity) are positive constants. Find the velocity of the object in the form of t. what is the differantial equation to solve this problem? dV =g- dt dV mv² =g+ k II → dt k dV = m – –V² dt III → - - dV k g--V dt IV → %3D m V → dV = mg – kV -
Transcribed Image Text:listory
Bookmarks
Window
Help
file:///Users/ahmadalsarraj/Desktop/sinav.karabuk.edu.tr.html
JB JetBrains Account
AL289
An object of mass m falls from rest, starting
at a point near the eart's surface. Assuming
that the air resistance is proportional to the
velocity magnitude of the object.
k(resistance coefficient), m(mass), g(gravity) are positive constants.
Find the velocity of the object in the form of t.
what is the differantial equation to solve this problem?
dV
I →
=g-
dt
k
m
dV
m
II →
= g +
k
dt
dV
Ш >
dt
k
M – –V²
k
dV
=g--V
dt
IV →
dV
= mg – kV
dt
V →
Sonraki O
MacBook Pro
Transcribed Image Text:ns - CAL289
dV
k
4-
dt
m
dV
m
-2
II
>
dt
dV
k
III
->
= M
dt
dV
IV →
dt
m
dV
= mg -kV
dt
A) II
B) II
C) I
D) IV
O EL V
Ma
With integration, one of the major concepts of calculus. Differentiation is the derivative or rate of change of a function with respect to the independent variable.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.