An object of mass 2 kg collides with an object of mass 1 kg that is at rest, as shown in the figure. A graph of the force as a function of time that the 1 kg object exerts on the 2 kg object is shown. After the collision, the 2 kg object has a speed of 2 , and the 1 kg object has a speed of 8 A student must determine the initial speed v of the 2 kg object. Which of the following options shows the correct substitutions into the equation Ap²= FÅt so that the initial speed of the unknown object can be determined?
An object of mass 2 kg collides with an object of mass 1 kg that is at rest, as shown in the figure. A graph of the force as a function of time that the 1 kg object exerts on the 2 kg object is shown. After the collision, the 2 kg object has a speed of 2 , and the 1 kg object has a speed of 8 A student must determine the initial speed v of the 2 kg object. Which of the following options shows the correct substitutions into the equation Ap²= FÅt so that the initial speed of the unknown object can be determined?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question
![+y
1 kg
2 kg
10,000
8000
2 6000
4000
2000
0.0010
0.0015
0.0020
0.0025
t (s)
An object of mass 2 kg collides with an object of mass
1 kg that is at rest, as shown in the figure. A graph of the
force as a function of time that the 1 kg object exerts on
the 2 kg object is shown. After the collision, the 2 kg object
has a speed of 2 , and the 1 kg object has a speed of 8 .
A student must determine the initial speed vo of the 2 kg
object. Which of the following options shows the correct
substitutions into the equation Ap³= FÅt so that the initial
speed of the unknown object can be determined?
(2 kg)(2 m – vo) = (8000 N)(0.00125 s), because
the maximum force exerted on the 2 kg object must be
considered.
(2 kg)(2 – vo) = } (8000 N)(0.00125 s), because
the average force exerted on the 2 kg object must be
considered.
(2 kg – 1 kg)(2 -vo) = (8000 N)(0.00125 s),
because the difference in mass and the maximum force
exerted on the 2 kg object must be considered.
(2 kg – 1 kg)(2 m/s – vo) = }(8000 N)(0.00125 s)
(D
,because the difference in mass and the average force
exerted on the 2 kg object must be considered.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F977bfee8-160f-43f3-bedb-5a30d488c484%2F3ce00694-bbd1-401d-83f0-7658104d5e24%2Fvcu7nxo_processed.jpeg&w=3840&q=75)
Transcribed Image Text:+y
1 kg
2 kg
10,000
8000
2 6000
4000
2000
0.0010
0.0015
0.0020
0.0025
t (s)
An object of mass 2 kg collides with an object of mass
1 kg that is at rest, as shown in the figure. A graph of the
force as a function of time that the 1 kg object exerts on
the 2 kg object is shown. After the collision, the 2 kg object
has a speed of 2 , and the 1 kg object has a speed of 8 .
A student must determine the initial speed vo of the 2 kg
object. Which of the following options shows the correct
substitutions into the equation Ap³= FÅt so that the initial
speed of the unknown object can be determined?
(2 kg)(2 m – vo) = (8000 N)(0.00125 s), because
the maximum force exerted on the 2 kg object must be
considered.
(2 kg)(2 – vo) = } (8000 N)(0.00125 s), because
the average force exerted on the 2 kg object must be
considered.
(2 kg – 1 kg)(2 -vo) = (8000 N)(0.00125 s),
because the difference in mass and the maximum force
exerted on the 2 kg object must be considered.
(2 kg – 1 kg)(2 m/s – vo) = }(8000 N)(0.00125 s)
(D
,because the difference in mass and the average force
exerted on the 2 kg object must be considered.
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