An object of mass 1 (kg) stretches a spring and is set in motion from a certain position. The damping constant of the spring is 2 (N · 8/m), and the spring constant in Hooke's law is 5 (N/m). During the motion there is an external force f(t) (N) acting on the mass such that f(t) = Acos(w(t – 4)). Then the displacement y = y(t) of the object from the equilibrium position satisfies /" + 2y' + 5y = A cos(w(t – $)).
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- A spring is resting vertically on a table. A small box is dropped onto the top of the spring and compresses it. Suppose the spring has a spring constant of 250 N/m and the box has a mass of 1.9 kg. The speed of the box just before it makes contact with the spring is 0.55 m/s. (a) Determine the magnitude of the spring’s displacement at an instant when the acceleration of the box is zero. (b) What is the magnitude of the spring’s displacement when the spring is fully compressed?A 10.6 kg object oscillates at the end of a vertical spring that has a spring constant of 2.05 ×104 N/m. The effect of air resistance is represented by the damping coefficient b = 3.00 N.s/m.(a) Calculate the frequency of the damped oscillation.(b) By what percentage does the amplitude of the oscillation decrease in each cycle?The unstretched length of a spring is 1.0 m with force constant is 50N/m. the spring is set into Simple Harmonic Motion by stretching it x distance before release. Determine the value of the mass attached to a spring if its period is twice as the period when spring acts as a simple pendulum. Find mass in kg.
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