An object moving with uniform acceleration has a velocity of 10.0 cm/s in the positive x-direction when its x-coordinate is 3.06 cm. If its x-coordinate 2.05 s later is -5.00 cm, what is its acceleration? X Express the position of the object in one-dimensional motion at constant acceleration as a function of time. Use the value of the expression at the two times to find the acceleration. cm/s² Need Help? Submit Answer Read It Master It

An object moving with uniform acceleration has a velocity of 10.0 cm/s in the positive x-direction when its x-coordinate is 3.06 cm. If its x-coordinate 2.05 s later is -5.00 cm, what is its acceleration? X Express the position of the object in one-dimensional motion at constant acceleration as a function of time. Use the value of the expression at the two times to find the acceleration. cm/s² Need Help? Submit Answer Read It Master It

Name: An object moving with uniform acceleration has a velocity of 10.0 cm/
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Description: An object moving with uniform acceleration has a velocity of 10.0 cm/s in the positive x-direction when its x-coordinate is 3.06 cm. If its x-coordinate 2.05 s later is -5.00 cm, what is its acceleration?XExpress the position of the object in one-di

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Use the negative sign from the equation s = 3t4 - 4t2
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The acceleration of a particle is given by a 3t-37, where a is in meters per second squared and tis in seconds. Determine the velocity and displacement as functions of time. The initial displacement at t=0 is so-8 m. and the initial velocity is vo-2 m/s. After you have the general expressions, evaluate these expressions at the indicated times. Answers: Att 5.5 s. 5 Att-10.5s, 5= m. v L m, m/s m/s
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Answer parts A and B
Plz plz solve for all parts … God bless
pls help me answer this with solution