An object moves with velocity as given in the graph below (in ft/sec). 10+ 9 8- 7-- 6- 5 10 12 14 -5- -6- -7-- -8- -9+ time (sec) After 14 seconds, How far is the object from where it started (Net Change)? What is the total distance the object traveled (Total Change)? Submit Question velocity (ft/sec) 4 3- 2 -1- -2 -3 -4 ft ft

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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**Educational Website Content:**

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### Velocity and Distance Calculation

**Scenario:**

An object moves with velocity as given in the graph below (in ft/sec).

**Graph Explanation:**

The graph provided plots velocity (in feet per second) against time (in seconds). 

1. The x-axis represents time, measured from 0 to 14 seconds.
2. The y-axis represents velocity, ranging from -9 ft/sec to 10 ft/sec.

The graph shows a linear increase in velocity from approximately -7.5 ft/sec at time t = 0 to approximately 9.5 ft/sec at t = 14 seconds.

**Questions:**

1. **After 14 seconds, how far is the object from where it started (Net Change)?**
2. **What is the total distance the object traveled (Total Change)?**

| **Net Change:** |  `________` ft  |
| **Total Change:** |  `________` ft  |

**Submit Question**

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Understanding the motion of this object requires assessing the area under the curve of the velocity-time graph, which corresponds to different components related to displacement and distance traveled.

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**Note:** The graph's increasing pattern exemplifies an object accelerating over time. The area under sections above the zero velocity line reflects positive displacement, while area below indicates negative displacement. Computing total distance considers the absolute values of these areas.

---

Ensure you use proper methods in either calculus (integral of the velocity function) or geometrical area calculations to find the correct displacement and total distance.
Transcribed Image Text:**Educational Website Content:** --- ### Velocity and Distance Calculation **Scenario:** An object moves with velocity as given in the graph below (in ft/sec). **Graph Explanation:** The graph provided plots velocity (in feet per second) against time (in seconds). 1. The x-axis represents time, measured from 0 to 14 seconds. 2. The y-axis represents velocity, ranging from -9 ft/sec to 10 ft/sec. The graph shows a linear increase in velocity from approximately -7.5 ft/sec at time t = 0 to approximately 9.5 ft/sec at t = 14 seconds. **Questions:** 1. **After 14 seconds, how far is the object from where it started (Net Change)?** 2. **What is the total distance the object traveled (Total Change)?** | **Net Change:** | `________` ft | | **Total Change:** | `________` ft | **Submit Question** --- Understanding the motion of this object requires assessing the area under the curve of the velocity-time graph, which corresponds to different components related to displacement and distance traveled. --- **Note:** The graph's increasing pattern exemplifies an object accelerating over time. The area under sections above the zero velocity line reflects positive displacement, while area below indicates negative displacement. Computing total distance considers the absolute values of these areas. --- Ensure you use proper methods in either calculus (integral of the velocity function) or geometrical area calculations to find the correct displacement and total distance.
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