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- An object is said to be truncated when part of the bottom is removed. The cut line must be parallel to the base. Many paper cups, such as the one shown here, are truncated cones. Calculate the capacity of this paper cup in millilitres. Assume these are interior measurements. 30.0 cm 5.0 cm 10 C 2.8 cm

- An object is said to be truncated when part of the bottom is removed. The cut line must be parallel to the base. Many paper cups, such as the one shown here, are truncated cones. Calculate the capacity of this paper cup in millilitres. Assume these are interior measurements. 30.0 cm 5.0 cm 10 C 2.8 cm

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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2. An object is said to be truncated when part of the bottom is removed. The cut line must be parallel to the base. Many paper cups, such as the one shown here, are truncated cones. Calculate the capacity of this paper cup in millilitres. Assume these are interior measurements. 30.0 cm 5.0 cm 10 cm 2.8 cm Hint 1 cm³ = 1 mL
Transcribed Image Text:2. An object is said to be truncated when part of the bottom is removed. The cut line must be parallel to the base. Many paper cups, such as the one shown here, are truncated cones. Calculate the capacity of this paper cup in millilitres. Assume these are interior measurements. 30.0 cm 5.0 cm 10 cm 2.8 cm Hint 1 cm³ = 1 mL
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