An object is projected upward with a 38 degree launch angle and an initial speed of 60 m/s. How high will the object be at the top of its trajectory?
An object is projected upward with a 38 degree launch angle and an initial speed of 60 m/s. How high will the object be at the top of its trajectory?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Projectile Motion Query**
**Problem Statement:**
An object is projected upward with a 38-degree launch angle and an initial speed of 60 m/s. How high will the object be at the top of its trajectory?
---
In this problem, the goal is to determine the maximum height reached by the object, which can be calculated by analyzing the vertical component of the object's initial velocity.
1. **Vertical Component of Velocity:**
- Initial speed (v₀) = 60 m/s
- Launch angle (θ) = 38 degrees
- Vertical component of velocity (v₀y) = v₀ * sin(θ)
2. **Maximum Height Calculation:**
- Use the formula for vertical displacement (height) at the peak:
\[
h = \frac{{v₀y^2}}{{2g}}
\]
where \( g \) is the acceleration due to gravity, approximately \( 9.81 \, \text{m/s}^2 \).
**Ensure to solve for \( h \) using the above principles in the study of projectile motion.**](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd20983e8-2b28-457f-b9e1-8150313039aa%2F93510f71-a29a-43fa-adfa-e7867c489938%2F0boerzm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Projectile Motion Query**
**Problem Statement:**
An object is projected upward with a 38-degree launch angle and an initial speed of 60 m/s. How high will the object be at the top of its trajectory?
---
In this problem, the goal is to determine the maximum height reached by the object, which can be calculated by analyzing the vertical component of the object's initial velocity.
1. **Vertical Component of Velocity:**
- Initial speed (v₀) = 60 m/s
- Launch angle (θ) = 38 degrees
- Vertical component of velocity (v₀y) = v₀ * sin(θ)
2. **Maximum Height Calculation:**
- Use the formula for vertical displacement (height) at the peak:
\[
h = \frac{{v₀y^2}}{{2g}}
\]
where \( g \) is the acceleration due to gravity, approximately \( 9.81 \, \text{m/s}^2 \).
**Ensure to solve for \( h \) using the above principles in the study of projectile motion.**
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