An object is placed against the center of a spherical mirror and then moved 70 cm from it along the central axis as the image distance i is measured. Figure 5 gives i versus object distance p out to ps = 40 cm. What is the image distance when the object is 70 cm from the mirror? p (cm) i (cm) 0 -10 -20 Ps
Q: A glass sphere (n = 1.50) with a radius of 16.0 cm has a tiny air bubble 6.00 cm above its center.…
A: The apparent depth of the bubble can be found using the concepts of refraction from spherical…
Q: A magnifying glass with focal length 15 cm is placed 10 cm above a stamp. The magnification of the…
A: If u is object distance , v is image distance and f is focal length if lens then 1v-1u=1f…
Q: The objective and the eyepiece of a microscope have focal lengths of +6mm and +45mm, respectively.…
A: Given that, the focal length of the objective is fo=6mm=0.6cm the focal length of the eyepiece is…
Q: The print in large print books averages 7.00 mm in height. How high is the image of the print on the…
A:
Q: An object is 1.40-cm-tall. It is placed a distance of 19.2 cm in front of a thin converging lens…
A: Lens Formula The focal length of a lens f, the object distance u and the image distance v for any…
Q: In an optical imaging system, which of following two planes are conjugate planes with magnification…
A: The principal planes are the planes in which the object produces its image of the same size. The…
Q: An object placed 12 cm from a concave mirror produces a real image 8.0 cm from the mirror. If the…
A:
Q: w9-4 A 1.80-cm-high object is placed 24.5 cm in front of a concave mirror with a 3.60 cm focal…
A: The objective of this question is to find the position of the image formed by a concave mirror when…
Q: very long cylindrical rod made of flint-glass (n=1.80) has its left end ground to a convex…
A: ng = 1.80 (refractive index of flint glass) R = +5 cm ( radius of convex hemisphere) u = - 8…
Q: Where is the focal point for a converging lens with object distance of 8 mm and image distance of 18…
A: Given that, For a converging lens, object distance u = 8 mm image distance v =18 mm We will use lens…
Q: a ray entering an optical system in a direction parallel to the optical axis will: A) pass through…
A: The rules of ray tracing for a thin lenses are * a ray entering converging lens parallel to its…
Q: A 2.0-cm tall object is 15 cm in front of a converging lens that has a 20 cm focal length. Determine…
A: We know that:-Lens formula:-1f=1u+1v here, f is focal lengthu is distance of objectv is distance…
Q: An object is placed 25 cm in front of a lens of focal length 20 cm. 60 cm past the first lens is a…
A:
Q: An object (height = 8.0 cm) and its image are both on the same side of a diverging lens. The object…
A: The image height is 4.8 cm
Q: calculate the location of the final image and compare it
A:
Q: When a young girl looks in a 6.0-cm radius, spherical Christmas tree ornament, she sees an imag How…
A:
Q: The power of a lens a. Approaches zero as the index of refraction increases O b. Increases as the…
A:
Q: Object -1 4 -4 -2 30 cm 1 f₁= 15 cm Left 40 cm f₂=20 cm A converging lens (f = 15 cm) and a second…
A: Write the equation of the first lens to calculate the image distance. 1f1=1v1+1u1115 cm=1v1+130…
Q: w9-5 An object is placed in front of a concave mirror with a 19.2 cm radius of curvature. A real…
A: The objective of this question is to find the distance of the object from the mirror when a real…
Q: I ← CONCAVE MIRROR Y O ← Di F Do f The figure shows light rays reflected from a concave spherical…
A:
Q: Objective: To determine the focal length of a lens. Procedure: three students measured the object…
A:
Q: The mirror equation relates the object distance, d0, the image distance, di, and the focal length,…
A: Given,
Q: Determine the image distance and size for a 10.00-cm tall object placed a) 60.0 cm b) 10 cm from a…
A: (a) given thatu = 60.0 cmho=10.00 cmf=30.0 cmv=?hi=?now using formula…
Q: 3.0-cm-high object is placed 10.0 cm from a concave mirror of focal length 4.0 cm. determine the…
A:
Q: 1. A person views a fish under water. If the fish is physically at a depth h = 1 m, what is the…
A: h=12m nw=1.333 na=1 in figure dapp is the apperant depth of fish. from snell law:-…
Q: to produce an image with a height of +10 cm when the object has a height of +1 cm, the magnification…
A:
Q: if an object with a height of 3 cm is imaged by an optical system with a magnification of -4, the…
A:
Q: A magnifying glass is a single convex lens with a focal length of f= 13.0 cm. What is the angular…
A: Given data: The focal length of the convex lens is f = 13.0 cm 1. Calculating the angular…
Q: Given the height of a cube is 2.55 mm and the length is 2.63 mm, what is the width of a cube on the…
A: Given Data: Height of the cube h=2.55 mm Length of cube l=2.63 mm
Step by step
Solved in 3 steps with 4 images
- A concave mirror is placed 10 cm in front of an object. The image measures 6 cm, and the image-mirror distance is 40 cm. Solve completely and find: a) radius of curvature in meters or cm and focal length in meters or cm b) magnification and the size of the object in cm c) Say if the image is real or virtual, if the image is reduced, the same size or enlarged and if the image is erect or inverted(9) Please don't write on a paper. I can't understand handwritten. Kathrine places a 6.95-cm tall candle a distance of 36.5 cm from a concave mirror. What is the height of the image when the focal length of the mirror is 50.0 cm? a. -135.14 cm b. 36.50 cm c. 25.72 cm d. 3.70 cmAn object is placed 15 cm from a concave mirror of focal length 8.0 cm. The object is 5.0 cm tall. How tall is the image? A. -5.71 cm B. 5.71 cm C. 4.43 cm D. -1.74 cm
- What range of do values will result in a virtual image? Infer this information for both the lens and mirror based on the data collected. Report these ranges in terms of f and/or 2f. For example, “When do is less than 2f.”1 + So 1 Thin Lens Equation: Mr = Si Yo So Principle Ray: the ray from object to lens that is parallel to the principle (optical) axis will refract in a path that intersects the image focal point. Focal Ray: the ray from the object whose path is directed towards the object focal point will refract in a path parallel the principle (optical) axis. Central Ray: the ray from the object whose path is directed towards the center of the lens (intersection with the principle axis) will emerge from the lens undeflected. Conventions: Quantity Sign Positive (+) Negative (-) Object distance So Real object Virtual object Image distance Si Real image Virtual image Focal length f Converging lens Diverging Lens (opposite side of o,i) Object height Yo Erect object Inverted object Image height Yi Erect image Inverted image Magnification (transverse) MT Erect image Inverted image For the following lens configurations, carefully generate a ray trace diagram to locate the image graphically. Use the thin…6
- 16) An object is located a distance do=5.1 cm in front of a concave mirror with a radius of curvature r = 24.5 cm. a) Write an expression for the image distance, di. b) Numerically, what is the image distance, di, in centimeters? c) Is this a real or virtual image?w9-19 physics An object is placed 20.0 cm from a converging lens with focal length 15.0 cm (see the figure, not drawn to scale). A concave mirror with focal length 10.0 cm is located 76.0 cm to the right of the lens. Light goes through the lens, reflects from the mirror, and passes through the lens again, forming a final image. d=76.0 What is the location of the final image? ______cm to the left of the lensThe focal length of a lens a. Approaches zero as the index of refraction increases b. Does not depend on the index of refraction O c. Increases as the index of refraction increases d. Decreases as the index of refraction increases