An object is placed 35 cm to the left of a converging lens with focal length f1=15 cm. A second converging lens with focal length f2=7 cm is placed a distance d=38 cm to the right of the first lens. What us the final image location relative to the second lens?
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An object is placed 35 cm to the left of a converging lens with focal length f1=15 cm. A second converging lens with focal length f2=7 cm is placed a distance d=38 cm to the right of the first lens. What us the final image location relative to the second lens?
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- An object with a height of -0.040 m points below the principal axis (it is inverted) and is 0.140 m in front of a diverging lens. The focal length of the lens is -0.25 m. (Include the sign of the value in your answers.) (a) What is the magnification? (b) What is the image height? m (c) What is the image distance? mA 1.00-cm-high object is placed 3.95 cm to the left of a converging lens of focal length 7.80 cm. A diverging lens of focal length –16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position 7.5 cm in front of the second lens v 0.5466 height Calculate the magnification produced by each lens. Then consider how the magnification relates image size and object size for each lens to find the height of the final image. cm Is the image inverted or upright? upright O inverted Is the image real or virtual? real virtualA nearsighted person has a far point of 25.3cm and is prescribed contact lenses to correct her vision. What lens strength (a.k.a., lens power), in Diopters, should be prescribed? Give your answer using the usual convention of positive values for converging lenses and negative values for diverging lenses.