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An object is moving along a linear path where v(t) = 4t - t². At time t = 1, the position of the object is 4. What is the formula that describes the object's position at time t = 7? Do not evaluate the integral. 7 o s(7) = 4 + √₁² (4u − u²) du ○ s(7) = √₁² (4u − u²) du ○ s(7) = 4 + √² (4u − u² ) du 7 ○s(7) = 4 - √₁² (4u – u²) du

An object is moving along a linear path where v(t) = 4t - t². At time t = 1, the position of the object is 4. What is the formula that describes the object's position at time t = 7? Do not evaluate the integral. 7 o s(7) = 4 + √₁² (4u − u²) du ○ s(7) = √₁² (4u − u²) du ○ s(7) = 4 + √² (4u − u² ) du 7 ○s(7) = 4 - √₁² (4u – u²) du

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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An object is moving along a linear path where v(t) = 4t - t². At time t = 1, the position of the object is 4. What is the formula that describes the object's position at time t = 7? Do not evaluate the integral. ○ s(7) = = 7 4 + √₁² (4u − u²) du s(7) = √₁² (4u − u²) du - - ○ s(7) = 4 + √² (4u − u²) du = 4 − ₁² (4u − u² ) du os(7)=
Transcribed Image Text:An object is moving along a linear path where v(t) = 4t - t². At time t = 1, the position of the object is 4. What is the formula that describes the object's position at time t = 7? Do not evaluate the integral. ○ s(7) = = 7 4 + √₁² (4u − u²) du s(7) = √₁² (4u − u²) du - - ○ s(7) = 4 + √² (4u − u²) du = 4 − ₁² (4u − u² ) du os(7)=
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