Problem 4An object is launched at a velocity of 25 m/s in a direction making an angle of 20° upward with the horizontal.What is the magnitude of the velocity of the object just before it hits the ground? **PHY 150 Problem Set 3****Projectile Motion Equations**1. **Horizontal Velocity:** \[ v_x = v_0 \cos \theta = \text{constant} \]2. **Vertical Velocity:** \[ v_y = v_0 \sin \theta \]3. **Vertical Velocity at some time \( t \):** \[ v_y = v_0 (\sin \theta) - gt \quad \text{where} \quad g = 9.8 \, \frac{m}{s^2} \]4. **Vertical Velocity at height \( y \):** \[ v_y^2 = (v_0 \sin \theta)^2 - 2g \Delta y \]5. **Horizontal Distance Traveled:** \[ \Delta x = v_0 (\cos \theta) t \]6. **Vertical Distance Traveled:** \[ \Delta y = (v_0 \sin \theta)t - \frac{1}{2} g t^2 \]7. **Time to Highest Point:** \[ t = \frac{v_0 \sin \theta}{g} \]8. **Total Flight Time:** \[ t = \frac{2 v_0 \sin \theta}{g} \]

Name: Problem 4An object is launched at a velocity of 25 m/s in a direction
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Description: Problem 4An object is launched at a velocity of 25 m/s in a direction making an angle of 20° upward with the horizontal.What is the magnitude of the velocity of the object just before it hits the ground? **PHY 150 Problem Set 3****Projectile Motion E

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College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Problem 4

An object is launched at a velocity of 25 m/s in a direction making an angle of 20° upward with the horizontal.

What is the magnitude of the velocity of the object just before it hits the ground?

**PHY 150 Problem Set 3**

**Projectile Motion Equations**

1. **Horizontal Velocity:**
\[
v_x = v_0 \cos \theta = \text{constant}
\]

2. **Vertical Velocity:**
\[
v_y = v_0 \sin \theta
\]

3. **Vertical Velocity at some time \( t \):**
\[
v_y = v_0 (\sin \theta) - gt \quad \text{where} \quad g = 9.8 \, \frac{m}{s^2}
\]

4. **Vertical Velocity at height \( y \):**
\[
v_y^2 = (v_0 \sin \theta)^2 - 2g \Delta y
\]

5. **Horizontal Distance Traveled:**
\[
\Delta x = v_0 (\cos \theta) t
\]

6. **Vertical Distance Traveled:**
\[
\Delta y = (v_0 \sin \theta)t - \frac{1}{2} g t^2
\]

7. **Time to Highest Point:**
\[
t = \frac{v_0 \sin \theta}{g}
\]

8. **Total Flight Time:**
\[
t = \frac{2 v_0 \sin \theta}{g}
\]

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