An object is launched at a velocity of 20 m/s in a direction making an angle of 25° upward with the horizontal. a) What is the maximum height reached by the object? b) What is the total flight time (between launch and touching the ground) of the object? c) What is the horizontal range (maximum x above ground) of the object?

An object is launched at a velocity of 20 m/s in a direction making an angle of 25° upward with the horizontal. a) What is the maximum height reached by the object? b) What is the total flight time (between launch and touching the ground) of the object? c) What is the horizontal range (maximum x above ground) of the object?

Similar questions

A projectile is launched at ground level with an intial vertical velocity of 25.0m/s and a horizontal velocity of 43.3m/s. It strikes a target above the ground 3.00 seconds later. a) How high is the target above the gound? b) How far did the projectile travel before hitting the target? c) What is the horizontal component of the velocity of the projectile right as it hits the target? d) What is the vertical component of the velocity of the projectile right as it hits the target?
You throw a ball up at some angle above the horizontal so that its velocity is (v0x, v0y). You then run 22.0 m forward on level ground and catch the ball 2.90 s later at the same altitude it was released from. a) How high above the release point did the ball reach? b) What was the horizontal component of the ball’s initial velocity, v0x? c) What was the vertical component of the ball’s initial velocity, v0y?
A ball is launched from a 10.0 m building with an initial speed of 15.0 ?/?. If the ball’s speed when it reaches its maximum height is 1/3 its speed when it is at half its maximum height, determine ball’s launch angle and the ball’s angle at impact. This is all the information i was given!
An arrow is launched from ground level, with an initial speed of 27.2 m/s at an angle of 31.4° above the horizontal. Neglect air resistance, and take upward as the positive direction. a) How much time is needed for the arrow to reach its maximum height, b) what is this maximum heightc) how long does it take to land on the ground againd) how far does it travel right before it lands.
Problem 4 An object is launched at a velocity of 25 m/s in a direction making an angle of 20° upward with the horizontal. What is the maximum height reached by the object?
For a projectile lunched with an initial velocity of v0 at an angle of θ (between 0 and 90o) , a) derive the general expression for maximum height hmax and the horizontal range R. b) For what value of θ gives the highest maximum height? Solution The components of v0 are expressed as follows: vinitial-x = v0cos(θ) vinitial-y = v0sin(θ) a) Let us first find the time it takes for the projectile to reach the maximum height. Using: vfinal-y = vinitial-y + ayt since the y-axis velocity of the projectile at the maximum height is vfinal-y = Then, = vinitial-y + ayt Substituting the expression of vinitial-y and ay = -g, results to the following: = - t Thus, the time to reach the maximum height is tmax-height = / We will use this time to the equation yfinal - yinitial = vinitial-yt + (1/2)ayt2 if we use the time taken to reach the maximum height, therefore, the displacement will yield the maximum height, so hmax = vinitial-yt + (1/2)ayt2 substituting, the vinitial-y expression above, results to…
1. The distance between home plate and the pitcher's mound in baseball is 60.5 ft. In MLB, baseballs are. pitched at about 90mph. Assume the ball is thrown perfectly horizontally, at 0°. How far in feet will the ball drop during its transit to home plate? Use g = 32 ft/s². (Note: this is why pitcher's mounds are raised.) 2. A pebble is tossed into the air at an angle of 62° above the horizontal, with an initial speed of 4.8 m/s. The pebble is 1.6m above the ground when it is released by the thrower's hand. a) How long will the pebble remain airborne? b) What maximum height above the ground will the pebble achieve?
A projectile is fired from point A at the edge of a cliff, whose initial velocity components are v0x = 60.0m / s and v0y = 175m / s. The projectile rises and then falls into the sea at point P. The projectile flight time is 40.0s and it does not experience appreciable air resistance in flight. a) Make a diagram of the problem, b) Determine how far it falls, c) what is the height of the cliff? and d) at what angle was it shot?
You shoot an arrow into the air at an initial velocity of 22.5 m/s at an angle of 40 degrees. a) Find the maximum height the arrow reaches in the air. b) Find the time it takes to reach its maximum height. c) Find the time it takes to hit the ground. Assume its flight in the air is symmetrical, with the first half of flight traveling upward, and the 2nd half of the flight traveling downward. Assume no air resistance. d) Find how far away it hits the ground.
A particle moves along xy-plane with a position of a (t) = sin(2t) + 3 cos(4t) y (t) = sin(t) – 6 cos(3t) = a Determine the position vector of the particle b. Determine the velocity vector of the particle c Determine the acceleration vector of the particle d Determine the position vector of the particle when I - 4 e Determine the average acceleration from t -0s to t- 5s f Determine the instantaneous acceleration when - is g Determine the average velocity from t- Is tot 3s
A rock was thrown horizontally from a 100.0 m high cliff. It strikes the ground 90.0 m from the base of the cliff. a) At what speed was it thrown? b) How long did it take to hit the ground. c) Neglecting wind resistance, which component of velocity is affected by gravity VERTICAL or HORIZONTAL? d) Sketch the trajectory of the rock as it falls to the ground and include the velocity vector at the beginning, midway down, and just before striking the ground. e) After you determine the total time in the air, you can then determine the final vertical velocity vector combined with the horizontal velocity determined earlier. Use these vectors to determine the resultant velocity vector just before landing. Recall using Pythagorean theorem to find the magnitude of the velocity vector and trigonometry for the angle below the horizontal that the resultant vector strikes at.
At a long distance shooting match, a bullet is fired with a muzzle velocity of 3000 feet per second from a rifle held in the horizontal position. When fired the sights of the rifle was dead center of a target. The bullet strikes the target at 4.00 ft below the center of the target. How long (in seconds) did it take for the bullet to reach the target? How far away (in unit of yards) was the target? Neglect any air resistance to the bullet. Make a simple sketch. Make a list of all given values, units, and the variables they represent. write the general form of the equation you are going to use. Insert the known values and solve. For problems with vertical motion State at the start of the problem which direction is positive by using an up or down arrow. Keep the velocity components and time to 2 decimal places