An object is launched at 9.8 meters per second (m/s) from a 73.5-meter tall platform. The equation for the object's height s at time t seconds after launch is s(t)=-4.9t^2+9,8t+73,5, where s is in meters. When does the object strike ground

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
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An object is launched at 9.8 meters per second (m/s) from a 73.5-meter tall
platform. The equation for the object's height s at time t seconds after launch is
s(t)=-4.9t^2+9.8t+73.5, where s is in meters. When does the object strike ground
and why?
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Transcribed Image Text:An object is launched at 9.8 meters per second (m/s) from a 73.5-meter tall platform. The equation for the object's height s at time t seconds after launch is s(t)=-4.9t^2+9.8t+73.5, where s is in meters. When does the object strike ground and why? Your answer Submit Never submit passwords through Google Forms This form was created inside of East Orange School District. Report Abuse edu 国 hp
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