**Problem:**An object is dropped from rest a distance \( d \) near the surface of Earth and takes time \( t \). If the same object is dropped from rest from a different height and takes time \( 2t \), it must have fallen a distance:- ○ \( \frac{1}{4}d \)- ○ \( \frac{1}{2}d \)- ○ \( 4d \)- ○ \( 2d \)- ○ \( d \)**Explanation:**This problem involves the physics of free fall, where the distance fallen under gravity is proportional to the square of the time of fall. The relevant equation for an object starting from rest is:\[ d = \frac{1}{2} g t^2 \]where \( d \) is the distance fallen, \( g \) is the acceleration due to gravity, and \( t \) is the time. Solving this equation for a time of \( 2t \) will allow us to determine the new distance fallen.

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Description: **Problem:**An object is dropped from rest a distance \( d \) near the surface of Earth and takes time \( t \). If the same object is dropped from rest from a different height and takes time \( 2t \), it must have fallen a distance:- ○ \( \frac{1}{4

The initial velocity of the object u=0 m/s When it falls from a height d its acceleration is a=9.8…

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An object is dropped from rest a distance d near the surface of Earth and takes time t. If the same object is dropped from rest from a different height and takes time 2t , it must have fallen a distance

An object is dropped from rest a distance d near the surface of Earth and takes time t. If the same object is dropped from rest from a different height and takes time 2t , it must have fallen a distance

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Newton's First Law of Motion

If a very smooth ball is rolled down an inclined surface with zero friction, the ball will continue to roll indefinitely for an infinite time, in an attempt to reach to the same height on the opposite hill!

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**Problem:**

An object is dropped from rest a distance \( d \) near the surface of Earth and takes time \( t \). If the same object is dropped from rest from a different height and takes time \( 2t \), it must have fallen a distance:

- ○ \( \frac{1}{4}d \)
- ○ \( \frac{1}{2}d \)
- ○ \( 4d \)
- ○ \( 2d \)
- ○ \( d \)

**Explanation:**

This problem involves the physics of free fall, where the distance fallen under gravity is proportional to the square of the time of fall. The relevant equation for an object starting from rest is:

\[ d = \frac{1}{2} g t^2 \]

where \( d \) is the distance fallen, \( g \) is the acceleration due to gravity, and \( t \) is the time. Solving this equation for a time of \( 2t \) will allow us to determine the new distance fallen.

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