An object is 20.8 cm to the left of a lens that has a focal length of +8.5 cm. A second lens, which has a focal length of -31 cm, is 5.28 cm to the right of the first lens.
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Q: 34. How far is the image from the lens? 4.5 cm 4 cm 6 cm 8 cm 12 cm 35. The image is: real and…
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Everything is right, I just need help with finding the overall magnification(Question 2)
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- a) Find an equation for the length L of a refracting telescope in terms of the focal length of the objective fo and the magnification m. L = (b) A knob adjusts the eyepiece forward and backward. Suppose the telescope is in focus with an eyepiece giving a magnification of 20.3. By what distance must the eyepiece be adjusted when the eyepiece is replaced, with a resulting magnification of 1.0 ✕ 102? Must the eyepiece be adjusted backward or forward? Assume the objective lens has a focal length of 2.32 m. (Use a positive value if the eyepiece must be moved forward toward the objective lens and negative values if the eyepiece must be moved backwards.) cm2) A person whose eyes are1.5 m above ground approaches a pool of water of depth 2m and length 1.5 m. At what distance from the edge of the pool will she first see a point at the bottom of the pool?A compound microscope has a distance of 161 mm between the objective lens and the eyepiece. The focal lengths of the objective and the eyepiece are 4.03 mm and 25.9 mm, respectively. Determine the magnitude of the total angular magnification ? of the microscope for a person whose near point is 25.0 cm away.
- A microscope has a tube length of 15.0 cm, an objective focal length of 2.3 cm, and an eyepiece focal length of 2.50 cm. What is the magnification of the microscope? Assume it is adjusted so that the eye is relaxed. Multiple choice possible answers: 44 54 55 4.4 Thanks!3. A cell phone has a fixed focal length lens of f = 3.85 mm = 0.00385 m and can take pictures over a range of distances from S. = 0.5 m to S,= infinity. Over what range of distances (S₁) does the lens in the cellphone have to move to focus an image at these two extremes in object distance?An olive is at the bottom of a glass of alcohol (n = 1.36), 6.00 cm beneath the surface. Above the alcohol is air. To a person in the air, who is directly above the olive, what is the apparent depth d' of the olive. d' = Number i Units
- I continue to get the wrong answer. TIA.A nearsighted person has a near point of 20.0cm and a far point of 60.0cm. When he wears his contact lenses, he can see faraway objects clearly. What is the closest distance at which he can see objects clearly when wearing his contact lenses? give the answer in cmThe figure gives the lateral magnification mof an object versus the object distance p from a lens as the object is moved along the central axis of the lens through a range of values for p out to p, = 22 cm. What is the magnification of the object when the object is 70 cm from the lens? 1.0 0.5 P's p (cm) Units Number