An object attached to a spring undergoes simple harmonic motion modeled by the differential equation d?y + ky O where y(t) is the displacement of the mass (relative to equilibrium) at time t, m is the т- dt? mass of the object, and k is the spring constant. A mass of 7 kilograms stretches the spring 0.2 meters. Use this information to find the spring constant. (Use g = 9.8 meters/second2) k = 343 The previous mass is detached from the spring and a mass of 11 kilograms is attached. This mass is displaced 0.35 meters above equilibrium (above is positive and below is negative) and then launched with an initial velocity of 3 meters/second. Write the equation of motion in the form y(t) = cq cos(wt) + c2 sin(wt). Do not leave unknown constants in your equation, and round all values to exactly 3 decimal places. y(t) = 0.74464 sin(4.5t) + 0.718 × Rewrite the equation of motion in the form y(t) = A sin(wt + ø) where o is an angle between and 2 Do not leave unknown constants in your equation, and round all values to exactly 3 decimal places. 2 y(t) 0.74464 sin(4.5t) + 0.718 ×