An object attached to a spring undergoes simple harmonic motion modeled by the differential equation k = m N/m d²x dt² where x(t) is the displacement of the mass (relative to equilibrium) at time t, m is the mass of the object, and k is the spring constant. A mass of 5 kilograms stretches the spring 0.05 meters. Use this information to find the spring constant. (Use g = 9.8 m/s²) + kx = 0 The previous mass is detached from the spring and a mass of 20 kilograms is attached. This mass is displaced 0.3 meters above equilibrium (above is positive and below is negative) and then launched with an initial velocity of 1 meters/second. Write the equation of motion in the form x(t) = c₁ cos(wt) + c₂ sin(wt). Do not leave unknown constants in your equation. x(t) = Rewrite the equation of motion in the form x(t) = A cos(Bt - ). Do not leave unknown constants in your equation. Leave as an angle between - π and T. x(t) =