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An object at the origin has an initial velocity of Vox = 5.4 m/s, voy = -4.8 m/s and a constant acceleration of ax = 1.2 m/s² and ay = 2.1 m/s². What is the angle of the position of the object, relative to the +x direction, 1.3 s later? 29° -79° -29° -61° 61° Submit Answer Hint Save for Later

An object at the origin has an initial velocity of Vox = 5.4 m/s, voy = -4.8 m/s and a constant acceleration of ax = 1.2 m/s² and ay = 2.1 m/s². What is the angle of the position of the object, relative to the +x direction, 1.3 s later? 29° -79° -29° -61° 61° Submit Answer Hint Save for Later

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Wondering if you can help me fins the position. I was able to calculate final velocities, but am unsure of how to fn the position given the information.

Voy Nox √x > √ 0 X I Vox = 5.4mls Voy = -4.8 m/s ax = 1.2m/s² ay = 2.1 m/s ² += 1.3 s K= V₁x + at Vy= Voy+ at V₁=5.4+ (1.2X1.3) V₁ = (-4.872.1)(1.3) Nx = 6.96 | V₁ = -2.07 N = 1.26 m/s ©
Transcribed Image Text:Voy Nox √x > √ 0 X I Vox = 5.4mls Voy = -4.8 m/s ax = 1.2m/s² ay = 2.1 m/s ² += 1.3 s K= V₁x + at Vy= Voy+ at V₁=5.4+ (1.2X1.3) V₁ = (-4.872.1)(1.3) Nx = 6.96 | V₁ = -2.07 N = 1.26 m/s ©
An object at the origin has an initial velocity of vox = 5.4 m/s, voy = -4.8 m/s and a constant acceleration of ax = 1.2 m/s² and ay = 2.1 m/s². What is the angle of the position of the object, relative to the +x direction, 1.3 s later? 29° -79° -29° -61° 61° Submit Answer Hint Save for Later
Transcribed Image Text:An object at the origin has an initial velocity of vox = 5.4 m/s, voy = -4.8 m/s and a constant acceleration of ax = 1.2 m/s² and ay = 2.1 m/s². What is the angle of the position of the object, relative to the +x direction, 1.3 s later? 29° -79° -29° -61° 61° Submit Answer Hint Save for Later
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