An object 1.3 cm high is held 3.3 cm from a person’s cornea, and its reflected image is measured to be 0.187 cm high. (a) Set-up the table for known and unknown quantities.(b) What is the magnification? (a) Set-up the table for known and unknown quantities.i) If quantities are unknown fill in the letter x (not captial X) from your keyboard.ii) Make sure to use the correct sign for the image distances, object distances, and the focal lengths.ii) Make sure to use the correct sign for the image and object heights. Inverted object amd imageheights are negative.iv) Do NOT do any calculations for this section.do =V cmd; =cmf =cmhoV cmh; =cmP =M=(b) What is the magnification?M =

Answered: Image /qna-images/answer/dbf84fac-cab8-4664-ae96-a27c7b564351.jpg

Answered: An object 1.3 cm high is held 3.3 cm…

Similar questions

A 2.5 cm-tall object stands in front of a converging lens. It is desired that a virtual image 2.6 times larger than the object be formed by the lens. How far from the lens (in cm) must the object be placed to accomplish this task, if the final image is located 13 cm from the lens? cm?
= 1.0). An object (A) is Assume that a thin lens (r, placed in the left side of lens (d = 45mm) and the image of the object is located in the right side of the lens at position (B) (d' = 90mm). 1) Compute the refraction index of the lens (n2); = -r2 = 40mm) is placed in the air (n 2) If placing another negative thin lens (f2 = -180mm) immediately behind the first lens to create a doublet lens in which the spacing between two lenses is zero (as shown in the right figure), what is the focal length of this doublet? 3) Where is the final image position (C) of the object (A) through this new doublet? (Note: Assuming this doublet lens is a combined thin lens too without considering its thickness).
an object of height 5 cm is placed 20 cm in front of a converging lens at focal length 10 cm. Behind the converging lens, and 25cm from it, there is a diverging lens of the focal length of 6 cm. Find the location of the final image, in centimeters, with respect to teh diverging lens. what is the magnification of the final image? what is the height of the final image?
The image distance for the lens of a person's eye is2.10 cm.Calculate the focal length of the eye's lens system for anobject (a) at infinity, (b) 500 cm from the eye, and (c) 25 cm from the eye.
What is a megapixel in a digital camera?(a) A large spot on the detector where the image isfocused.(b) A special kind of lens that gives a sharper image.(c) A number related to how many photographs thecamera can store.(d) A million light-sensitive spots on the detector.(e) A number related to how fast the camera can takepictures.

An object 1.3 cm high is held 3.3 cm from a person’s cornea, and its reflected image is measured to be 0.187 cm high. (a) Set-up the table for known and unknown quantities. (b) What is the magnification?